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miss Akunina [59]
3 years ago
14

A baseball player got 61 hits one season. He got h of the hits in one game. What expression represents the number of hits he got

in the rest of the​ games? The player had nothing hits in the rest of the games.
Mathematics
1 answer:
mina [271]3 years ago
7 0

Answer:

(61-h)

Step-by-step explanation:

Total number of hits by baseball player in one season = 61

Number of hits in one game = h

To find:

The expression to represent the number of hits that the player got in the rest of the games = ?

Solution:

Number of hits that the player got in one game = h

Let the number of hits that the player got in rest of the games = x

As per the given question statement,

The sum of h and x will be equal to 61.

h+x=61\\\Rightarrow \bold{x =61-h}

Therefore, the player had (61-h) hits in the rest of the games.

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We have 2l + 2w = 120 and l/w = 2/3;
Then, l = (2/3)w;
Finally, (4/3)w + 2w = 120;
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3 years ago
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A well-known brokerage firm executive claimed that at least 41 % of investors are currently confident of meeting their investmen
atroni [7]

Answer:

z=\frac{0.398 -0.41}{\sqrt{\frac{0.41(1-0.41)}{88}}}=-0.229

Step-by-step explanation:

1) Data given and notation n  

n=88 represent the random sample taken

X=35 represent the adults that said they are confident of meeting their goals

\hat p=\frac{35}{88}=0.398 estimated proportion of adults that said they are confident of meeting their goals

p_o=0.41 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that that at least 41 % of investors are currently confident of meeting their investment goals.:

Null hypothesis:p=0.41  

Alternative hypothesis:p < 0.41  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.398 -0.41}{\sqrt{\frac{0.41(1-0.41)}{88}}}=-0.229

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This methos is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level is not provided, but we can assume \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a unilateral test the p value would be:  

p_v =P(z  

Using the p value obtained and the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of of investors that are currently confident of meeting their investment goals is not significantly lower than 0.41 or 41%.  

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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