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satela [25.4K]
3 years ago
6

Please help!! ASAP

Mathematics
1 answer:
topjm [15]3 years ago
5 0

Answer:

11in

Step-by-step explanation:

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step 2. multiply the decimal value with the main number
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CUMPLEIE
beks73 [17]

the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake is 3.7

<u>Step-by-step explanation:</u>

Here we have , to find  the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake . Let's find out:

We know that , Value of earthquake is given by formula

⇒ M = Log(\frac{I_1}{I_0} ) , Where M is magnitude of earthquake

I_1  is the measured magnitude of intensity of  earthquake .

I_0  is the standard magnitude of intensity of  earthquake .

According to question , I_1 = 5011I_0 , Hence

⇒ M = Log(\frac{I_1}{I_0} )

⇒ M = Log(\frac{5011(I_0)}{I_0} )

⇒ M = Log(5011 )

⇒ M =3.69924    { On rounding off we get }

⇒ M =3.7

Therefore , the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake is 3.7

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3 years ago
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