Answer:
Step-by-step explanation:
The system of equations given are:
5x - y + z = -6 ------------- i
2x + 7y + 3z = 8 ---------- ii
x + 2z = 6 ----------------- iii
Let us deal with equation i and ii first since they have 3 variables x, y and z;
5x - y + z = -6 x 7
2x + 7y + 3z = 8 x 1
35x - 7y + 7z = -42 ---- iv
2x + 7y + 3z = 8 ---- v
Add equation iv and v;
37x + 10z = -34 ------vi
So, let us solve equation vi and iii:
x + 2z = 6 - ---------- iii x 10
37x + 10z = -34 --- iv x 2
10x + 20z = 60 vi
74x + 20z = -68 vii
Subtract vi - vii;
-64x = 128
x = -2
So; put x = -2 into iii;
x + 2z = 6
-2 + 2z = 6
2z = 6 + 2 = 8
z = 4
Put x = -2 and z = 4 into equation i;
5(-2) - y + 4 = - 6
-10 -y +4 = -6
-6 - y = -6
-y = 0
y = 0
Answer:
Im sorry bro but there's no picture
Step-by-step explanation:
I could be very wrong, but I believe the answer is C
Question 1)
Volume of Tank A = Sum of volume of its two parts.
So,
Volume of Tank A = 24 + 96 = 120 cubic feet
Question 2)
Volume of Tank B and Tank A is the same. So, Volume of Tank B = 120 cubic feet
One section of Tank B = 45 cubic feet
So, volume of other section of tank B = 120 - 45 = 75 cubic feet
distance between two points is [(x2-x1)^2 +(y2-y1)^2]^1/2
I.e,[{5-1)^2+(0-3)^2]^1/2
[16+9]^1/2
[25]^1/2
5
