Answer:
Y/6 <_ 2
Step-by-step explanation:
(Less than it equal to sign)
Answer:
The first answer one is true
Answer:
Lets a Go!!
Step-by-step explanation:
i) (3x + y) + 2 y (x-4)
= 3x+y + 2yx - 8y
= 3x-7y+2yx
This is the simplest form of equation
Answer:
B a b^2 c^5/ d^4
Step-by-step explanation:
a^-3 b^2 c^3 d^-3 / (a^-4 b^-2c^-2d)
separate the terms
a^-3/a^-4 * b^2/b^-2 * c^3 /c^-2 d^-3 /d
when dividing, we subtract the exponents
a^ (-3--4) b^(2--2) c^(3--2) d^(-3-1)
a^ (-3+4) b^(2+2) c^(3+2) d^(-3-1)
a^1 b^2 c^5 d^-4
negative exponent go to the denominator if they are in the numerator
a b^2 c^5/ d^4
Answer:
Step-by-step explanation:
The depreciation of the value for a car is modeled by the equation y = 100,000(.85)^x for x years since 2000
a) for the value to be $61,412.50, then
61412.50 = 100000(.85)^x
61412.50/100000 = 0.85^x
0.614125 = 0.85^x
We would take log to base 10 of both sides. It becomes
Log 0.614125 = log 0.85^x =
x log0.85
- 0.2117 = x × - 0.07058
- 0.2117 = - 0.07058x
x = - 0.2117/- 0.07058
x = 3 years
b) 1/4 × 100000 = 25000
Therefore ,
25000 = 100000(.85)^x
25000/100000 = 0.85^x
0.25 = 0.85^x
We would take log to base 10 of both sides. It becomes
Log 0.25 = log 0.85^x =
x log0.85
- 0.602 = x × - 0.07058
- 0.602 = - 0.07058x
x = - 0.602/- 0.07058
x = 9 years