Answer:
Yes, both of these segments (A and B) will be directed to the same socket at Host C .
Explanation:
Suppose both Host A and Host B each send a UDP segment to Host C with destination port number 6789, surely , both of these segments will be directed to the same socket at Host C .
Reason being that, the operating system will provide the process with the IP details to distinguish between the individual segments arriving at host C- for each of the segments (A and B) recieved at Host C.
Answer:
The answer is Upload bandwidth
Explanation:
Bandwidth refers to the highest transfer rate of data on an internet connection or network.
Upload bandwidth is the amount of data that moves from a computer to the internet or a network within a given amount of time. Documents, music files, video files, software and so on can be uploaded to the internet or a network.
One 4-GB DIMM. Dont really have a explanation for it just comes from previous experience
<u>Answer:</u>
<em>using System;
</em>
<em>public class Program
</em>
<em>{
</em>
<em> public static void Main()
</em>
<em> {
</em>
<em> String input ;
</em>
<em> while(true)
</em>
<em> {
</em>
<em> input = Console.ReadLine();
</em>
<em> if(input.Equals(""quit""))
</em>
<em> break;
</em>
<em> Reverse_String(input);
</em>
<em> }
</em>
<em> return;
</em>
<em> }
</em>
<em>static void Reverse_String(string input_text)
</em>
<em>{
</em>
<em> char[] text = input_text.ToCharArray();
</em>
<em> Array.Reverse(text);
</em>
<em> Console.WriteLine(text);
</em>
<em>}
</em>
<u>Explanation:</u>
<em>In the above program a separate function is written to reverse the string.</em>
This method takes the string as an argument and place it in a array and then use the built-in function reverse and print the reversed string in the console.
<em>In the main(), the input is obtained from the console and it is passed to the reversestring().
</em>
To <span>rite a statement that terminates the current loop when the value of the int variables x. and y.are equal please check below:
</span>
if (x == y) break; // exit loop
I hope the answer will help you. Thank you.
