When a function template has two parameterized types, one as the return value, and one as an argument, then THE FIRST TIME MUST BE EXPLICITLY CODED.
Explanation:
- The act of implicit and explicit coding, and implicit and explicit code, is defined by context of execution of additional behavior or type setting/casting. Specifically, implicit or explicit methods are defined by the contexts in which they are meant to be used.
- The explicit coding discipline favors clear and explicit expression of intent in the code.
- The uses-cases dictate the structure of the application. What the application does should not be implicitly hidden in an organization that the framework is trying to dictate you. Avoid having folders like /controllers, /views at the highest level of folders organization, in favor of folders containing features and use-cases: /categories, /products, etc.
- Template parameter represents a type that has not yet been specified, but that can be used in the template function as if it were a regular type.
Answer:
discriminant = b * b - 4 * a * c
discriminant = b ** 2 - 4 * a * c
Explanation:
The operands are correct and in the right order (for python).
** is the operand for squaring something.
* is the operand for multiplying something.
- is the operand for subtracting something.
All of the above
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Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
