Answer:
The answer would be 17
Step-by-step explanation:
Answer:
56756
Step-by-step explanation:
Answer:
The null and alternative hypothesis are:
There is sufficient evidence to support the claim that the mean tornado length is greater than 2.6 miles
Step-by-step explanation:
Consider the provided information.
The claim that the mean tornado length is greater than 2.6 miles.
If there is no statistical significance in the test then it is know as the null which is denoted by , otherwise it is known as alternative hypothesis which denoted by .
Therefore, the required null and alternative hypothesis are:
significance level α =0.05
From the given table the test statistic T=2.230166
P-value is 0.0131
0.0131<0.05
P value is less than the significance level, so reject the null hypothesis.
There is sufficient evidence to support the claim that the mean tornado length is greater than 2.6 miles
Given that 4000 items are checked in one month, let the number of detective items be represented as y.
Quality control finds on average that 0.026% of the items in the factory are detective. This implies that
When 4000 items are checked, we have the number of detective items to be evaluated as
Hence, the number of detective items is 1.04.
What I always do to solve this, is find a common factor for each number first.
Usually 4 or 5 works best. I'll use 4.
4 goes into 80 20 times, which means that 4 = 5% of 80.
If 4 = 5%, and 48 = 12 x 4, then 48 must equal 60% of 80.
(Another way to solve this problem is: simplify 48 / 80. This simplifies to 3/5.
3/5 = 60%)!