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Yuliya22 [10]
3 years ago
10

if you draw one card from a standard deck, what is the probability of drawing a diamond or a red card?​

Mathematics
1 answer:
Aleks [24]3 years ago
4 0

Answer:

3/4 probability

probability to draw a red card = 11/26

probability to draw a diamond =1/4

probability of drawing one or other card = 35/52

# actually i am not sure

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Translate the inequality and solve. Negative three times a number is less than six.
mart [117]

Answer:

x>-2

Step-by-step explanation:

The translated inequality to be solved is -3x<6

You divide -3 by both sides which switches the sign because it is negative, there fore the answer is x>-2.

4 0
3 years ago
Read 2 more answers
If f(x) = 3x + 2, what is f(5)?​
MrRa [10]

Answer:

f(5) = 17

Step-by-step explanation:

plug in 5 in the x so 3(5)+2 =17

5 0
3 years ago
Read 2 more answers
the ratio of the angle measures of a triangle are 3:3:4 what angle measures the triangles classification ​
TEA [102]

Step-by-step explanation:

sum of the ratio=3+3+4=10

now,

angle I = 3/10×180=54

angle II= 3/10×180=54

angle III=4/10×180=72

that shows th given triangle is isoceles

6 0
2 years ago
What did I do wrong so I don’t do it again on the test
denpristay [2]

Answer:

nothing

Step-by-step explanation:

all of them seem to be right. if you need practice work on alternate interior angles, exterior angles

8 0
2 years ago
15 points!!! GEOMETRY help please!!<br> Questions attached!
dolphi86 [110]
3. Look at the picture.

We have the right angle triangle. We know the sum of measures of angles in triangle is equal 180°. Therefore:

x^o+90^o+43^o=180^o\\\\x^o+133^o=180^o\ \ \ |-133^o\\\\x^o=47^o

Answer:\ \boxed{47^o}

4.
Look at the picture.

Use Pythagorean theorem:

x^2+14^2=(10+x)^2\\\\x^2+196=10^2+2\cdot10\cdot x+x^2\ \ \ \ |-x^2\\\\196=100+20x\ \ \ |-100\\\\20x=96\ \ \ |:20\\\\x=4.8

Used:\ (a+b)^2=a^2+2ab+b^2

Answer:\ \boxed{4.8\ units}

5.
TRUE: 1; 2; 4

6.
We find a slope of the line OP:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\O(2;\ 6)\to x_1=2;\ y_1=6\\\\P(4;\ 3)\to x_2=4;\ y_2=3\\\\m=\dfrac{3-6}{4-2}=\dfrac{-3}{2}

We have: OP:\ y=-\dfrac{3}{2}x+b

Now, we must find the slope of the line perpendicular to the line OP.
We know:

k:y=m_1x+b;\ l:y=m_2x+c\\\\k\ \perp\ l\iff m_1m_2=-1

therefore

-\dfrac{3}{2}m_2=-1\ \ \ |\cdot\left(-\dfrac{2}{3}\right)\\\\m_2=\dfrac{2}{3}

So. We have the answer! :)

Answer:\ \boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}}

6 0
2 years ago
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