The general formula for a equation of the form:
![ax^2+bx+c=0](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0)
is:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
In this case we notice that a=1, b=-4 and c=3. Plugging this values in the general formula we get:
![\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(1)(3)}}{2(1)} \\ =\frac{4\pm\sqrt[]{16-12}}{2} \\ =\frac{4\pm\sqrt[]{4}}{2} \\ =\frac{4\pm2}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-%28-4%29%5Cpm%5Csqrt%5B%5D%7B%28-4%29%5E2-4%281%29%283%29%7D%7D%7B2%281%29%7D%20%5C%5C%20%3D%5Cfrac%7B4%5Cpm%5Csqrt%5B%5D%7B16-12%7D%7D%7B2%7D%20%5C%5C%20%3D%5Cfrac%7B4%5Cpm%5Csqrt%5B%5D%7B4%7D%7D%7B2%7D%20%5C%5C%20%3D%5Cfrac%7B4%5Cpm2%7D%7B2%7D%20%5Cend%7Bgathered%7D)
then:
![x_1=\frac{4+2}{2}=\frac{6}{2}=3](https://tex.z-dn.net/?f=x_1%3D%5Cfrac%7B4%2B2%7D%7B2%7D%3D%5Cfrac%7B6%7D%7B2%7D%3D3)
and
![x_2=\frac{4-2}{2}=\frac{2}{2}=1](https://tex.z-dn.net/?f=x_2%3D%5Cfrac%7B4-2%7D%7B2%7D%3D%5Cfrac%7B2%7D%7B2%7D%3D1)
Therefore, x=3 or x=1.
So we start out by finding out what 80% of 500 is by,
500 * .80 = 400
So if 80% is 400 that means that there is still space available for 100 more gallons!
How the heck did we know that?!?
simple 500- 400= 100
So that leaves us knowing that there are 100 gallons left that can be held!! :)
So your answer is 100 gallons!!
I hope that this helped!
Answer:
12
Step-by-step explanation:
12-8=4
p=12
Answer:
1
Step-by-step explanation:
Hope this will help:)