Answer:
B.) It is equal to about 1 times the mean absolute deviation of either data set.
Explanation:
Given the scores :
Williams :
89,97, 78, 81, 91
Andre :
90, 74, 73, 87, 82
The mean scores :
Mean = ΣX / n
William's mean score = 436 / 5 = 87.2
Mean absolute deviation :
[|89-87.2| + |97-87.2| + |78-87.2| +|81-87.2| + |91-87.2|] / 5
William's mean absolute deviation = 6.16
Andre's mean score = 406 / 5 = 81.2
Andre's mean absolute deviation =
[|90-81.2| + |74-81.2| + |73-81.2| +|87-81.2| + |82-81.2|] / 5 = 6.16
Difference of the mean = 87.2 - 81.2 = 6
Mean absolute deviation of each dataset = 6.16
The closest relationship between the mean difference and the mean absolute deviation is :
Mean difference is about 1 times the mean absolute deviation
