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3 years ago

50 points!!!!!!!

Mathematics

2 answers:

MrMuchimi3 years ago

7 0

They have to travel 135.714286 feet per hour
So probably yes

Neko [114]3 years ago

7 0

Answer:

Depends on how fast they climb. If we knew how fast they climb then we can tell, but without knowing how fast they climb we can't tell.

Step-by-step explanation:

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Television viewers cast votes to decide the winners in different rounds of a singing competition. The number of votes cast in th

Mashutka [201]

Answer:

the answer is D Round 2 np

8 0

3 years ago

Read 2 more answers

36.18 litres = _____ litres ______millilitres

german

36 litres 180 millilitres

Hope this helps!

5 0

2 years ago

Write an equation for the line of best fit

Mariana [72]

Hi the answer is y=mx+ b10

7 0

3 years ago

Which is the equation of a hyperbola with directrices at y = ±2 and foci at (0, 4) and (0, −4)?

Advocard [28]

Answer:

Step-by-step explanation:

First off, I'm assuming that when you said "directrices" you mean the oblique asymptotes, since hyperbolas do not have directrices they have oblique asymptotes.

If we plot the asymptotes and the foci, we see that where the asymptotes cross is at the origin. This means that the center of the hyperbola is (0, 0), which is important to know.

After we plot the foci, we see that they are one the y-axis, which is a vertical axis, which means that the hyperbola opens up and down instead of sideways. Knowing those 2 characteristics, we can determine that the equation we are trying to fill in has the standard form

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1$

We know h and k from the center, now we need to find a and b. Those values can be found from the asymptotes. The asymptotes have the standard form

y = ± $\frac{a}{b}(x-h)+k$

Filling in our asymptotes as they were given to us:

y = ± $\frac{2}{1}(x-0)+0$ where a is 2 and b is 1. Now we can write the formula for the hyperbola!:

$\frac{(y-0)^2}{4}-\frac{(x-0)^2}{1}=1$ which of course simplifies to

$\frac{y^2}{4}-\frac{x^2}{1}=1$

4 0

4 years ago

a water tank holds 24,000 gallons. how many hours will it take for 2/3 of the water to be used if the water is used at an averag

Likurg_2 [28]

In the question, it is already mentioned that the water tank holds = 24,000 gallons
In the given question it is also mentioned that the need is to find the time required to use 2/3 of the total water that the tank holds.
So the need is to find the amount of water that equals 2/3 of the total water in the tank.
Then
Quantity of water that needed to be used = [24000 * (2/3)] gallons
= 16000 gallons
In the problem it is also mentioned that the average rate of consumption per day is 650 gallons.
So
650 gallons of water used in = 24 hours
16000 gallons of water will be used in = [(24/650) *16000] hours
= 590.77 hours
So the time required to consume 2/3 of the total water in the tank is 590.77 hours.

8 0

4 years ago