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8_murik_8 [283]
3 years ago
7

Out of the 100 cells shown how many are in the process of dividing?

Mathematics
1 answer:
givi [52]3 years ago
6 0
Over 97% would be dividing
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Kamran wins the big game lottery. He invests part of his winnings in treasury bonds promising a 5% annual return and he deposits
Ostrovityanka [42]

Answer:

Amount won by Kamran = $21,450

Step-by-step explanation:

This can be calculated using the following 3 steps:

Step 1: Calculation of the amount invested in treasury bonds

Since the limit to the duration of investment is not stated, the amount invested can be calculated using the formula for calculating the present value of a perpetuity as follows:

PV = P / r …………………………………. (1)

Where;

PV = Present value or the amount invested treasury bonds = ?

P = Annual return on his investments = $661.25

r = Annual rate of return = 5%, or 0.05

Substitute the values into equation (1), we have:

PV = $661.25 / 0.05 = $13,225

Step 2: Calculation of the amount deposited in the money market account

From Step 1 above, we have:

Amount invested treasury bonds = $13,225

Since he invests $5000 more in treasury bonds than he deposits in the money market account, the amount deposited in the money market account can be calculated as follows:

Amount deposited in the money market account = Amount invested treasury bonds - $5,000 = $13,225 - $5,000 = $8,225

Step 3: Calculation of the amount won by Kamran

Amount won by Kamran = Amount invested treasury bonds + Amount deposited in the money market account = $13,225 + $8,225 = $21,450

7 0
3 years ago
Stanley has a collection of seashells. He found 35% of his collection on Florida beaches. If Stanley has 49 seashells from Flori
m_a_m_a [10]

Answer:

The number of seashells he have in his collection all together is <u>140</u>.

Step-by-step explanation:

Given:

Stanley has a collection of seashells. He found 35% of his collection on Florida beaches.

Stanley has 49 seashells from Florida.

Now, to find the number of seashells of his collection altogether.

Let the number of seashells all together be x.

Percentage of seashells found on Florida beaches = 35%.

Number of seashells found on Florida beaches = 49.

Now, to get the number of seashells altogether we put an equation:

35\%\ of\ x=49.

⇒ \frac{35}{100} \times x=49

⇒ 0.35\times x=49

⇒ 0.35x=49

Dividing both sides by 0.35 we get:

⇒ x=140.

Therefore, the number of seashells he have in his collection all together is 140.

4 0
3 years ago
For his birthday, Tyrone's parents gave him $7,790.00 which they put into a savings account that earns 15% interest compounded m
torisob [31]

Answer:

5 years and 5 months

Step-by-step explanation:

<u />

<u>Compound Interest Formula</u>

\large \text{$ \sf A=P(1+\frac{r}{n})^{nt} $}

where:

  • A = final amount
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • A = $17,474.00
  • P = $7,790.00
  • r = 15% = 0.15
  • n = 12
  • t = number of years

Substitute the given values into the formula and solve for t:

\implies \sf 17474=7790\left(1+\dfrac{0.15}{12}\right)^{12t}

\implies \sf \dfrac{17474}{7790}=\left(1.0125}\right)^{12t}

\implies \sf \ln\left(\dfrac{17474}{7790}\right)=\ln \left(1.0125}\right)^{12t}

\implies \sf \ln\left(\dfrac{17474}{7790}\right)=12t \ln \left(1.0125}\right)

\implies \sf t=\dfrac{\ln\left(\frac{17474}{7790}\right)}{12 \ln \left(1.0125}\right)}

\implies \sf t=5.419413037...\:years

Therefore, the money was in the account for 5 years and 5 months (to the nearest month).

3 0
2 years ago
Read 2 more answers
Need hello fast I don’t know what to do
Free_Kalibri [48]

35 + 14
The greatest common factor for both is 7. Factor out 7

7(5 + 2) is your answer

Hope this helps

8 0
3 years ago
Three teams, A, B and C, play in a competition.
VladimirAG [237]

Answer:

A = 24

B = 8

C = 6

Step-by-step explanation:

4:3 from B:C

8:6

8 games won by B and 6 games won by C.

3:1 from A:B

24:8

24 by A and 8 by B

8 0
3 years ago
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