From 6,1 to 7,4
We can determine the slope of the line
rise/run
3/1=3
Now we know the slope of the line, a line parallel to it must obtain the same slope, therefore, I tried to see if the increase in y is three times the increase in x
I found the true pair to be A
(-4,1) and (-2,7)
Answer: y = -14/9(x + 4)^2 + 7
Step-by-step explanation:
The given roots of the quadratic function is (-1, -7)
The vertex is at (-4, 7)
The formula is
y = a(x - h)^2 + k
The vertex is (h, k)
Comparing with the given vertex, (-4, 7), h = -4 and k = 7
Substituting into the formula
y = a(x - h)^2 + k, it becomes
y = a(x - - 4)^2 + 7
y = a(x + 4)^2 + 7
From the roots given (-1, -7)
x = -1 and y = -7
Substituting x = -1 and y = -7 into the equation,
y = a(x + 4)^2 + 7, it becomes
-7 = a(-1+4)^2 + 7
-7 = a(3^2 ) + 7
- 7 = 9a + 7
-7-7 = 9a
9a = -14
a = -14/9
Substituting a = - 14/9 into the equation, it becomes
y = -14/9(x + 4)^2 + 7
Hello,
we know that lim sin x /x =1 when x->0
lim sin(9x)/6x=1/6 lim sin (9x)/ x=1/6 lim sin( 9x) /(9x) *9=9/6=3/2
The answer you are looking for is x=-2.
Solution/Explanation:
Writing out the equation
3[-x+(2x+1)]=x-1
Simplifying inside of the brackets first
Combining like terms, since -x+2x=x
3(x+1)=x-1
*You can remove the parenthesis, if preferred.
Using the Distributive Property on the left side of the equation
3x+3=x-1
Now, subtracting the "x" variable from both sides
3x+3-x=x-x-1
"x-x" cancels out to 0.
3x+3-x=-1
Combining like terms and simplifying
3x-x+3=-1
2x+3=-1
Subtracting 3 from both sides of the equation
2x+3-3=-1-3
"3-3" cancels out to zero.
2x+0=-1-3
2x=-1-3
Simplifying the right side of the equation
2x=-4
Finally, dividing both sides by 2
2x/2=-4/2
Simplifying the final part of the problem
Since 2x/2=x and -4/2=-2
x=-2
So, therefore, the final answer is x=-2.
Hope that this has helped you. Good day to you.
Answer:
$17.21
Step-by-step explanation:
Just line up the decimals and then you add. But after you finished adding, make sure you just straight up bring the decimal down to your final answer to the question.
