Answer:
139,999
Step-by-step explanation:
If the digit sum of n is divisible by 5, the digit sum of n+1 can't physically be divisble by 5, unless we utilise 9's at the end, this way whenever we take a number in the tens (i.e. 19), the n+1 will be 1 off being divisble, so if we take a number in the hundreds, (109, remember it must have as many 9's at the end as possible) the n+1 will be 2 off being divisble, so continuing this into the thousands being three, tenthousands being 4, the hundred thousands will be 5 off (or also divisble by 5). So if we stick a 1 in the beginning (for the lowest value), and fill the last digits with 9's, we by process of elimination realise that the tenthousands digit must be 3 such that the digit sum is divisible by 5, therefore we get 139,999
Answer:
step one simply hope it helped!
Step-by-step explanation:
3,5,8,11,17-35odd,47,54,70,78,80,81 pls help
nirvana33 [79]
Answer:
54, 78, 70, 47, 80, 81,
Step-by-step explanation:
I ate them
Step-by-step explanation:
because I was hungry and I need a brain
= (1 - tan^2 (x)) / (1 + tan^2 (x))
= (1 - (-4/3)^2) / (1 + (-4/3)^2)
= (1 - (16/9)) / (1 + (16/9))
= (9 - 16) / (9 + 16) [By multiplying numerator and denominator with 9]
= (-7) / (25)
= -7/25
