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Zarrin [17]
3 years ago
11

‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎

‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎​

Mathematics
2 answers:
Luba_88 [7]3 years ago
8 0

Answer: you need to show the rest because i dont know. four times what?

Step-by-step explanation:

...

Zolol [24]3 years ago
4 0
Hope this helps!
1. Gallons
2. G, gallons
3. 4
4. 4g
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Mookie Betts of the Boston Red Sox had the highest batting average for the 2018 Major League Baseball season. His average was 0.
Annette [7]

Answer:

Binomial probability, with n = 5, p = 0.352

Step-by-step explanation:

For each time Mookie Betts went to bat, there were only two possible outcomes. Either he got a base-hit, or he did not. The probability of getting a hit on each at-bat is independent of any other at-bat. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

His average was 0.352.

This means that p = 0.352

Assume he has five times at bat tonight in the Red Sox-Yankees game.

This means that n = 5

a. This is an example of what type of probability

Binomial probability, with n = 5, p = 0.352

8 0
3 years ago
Pls be right will give brainliest :3
Vedmedyk [2.9K]
A:5

I hope this helps you
Good luck on the rest :)
7 0
3 years ago
Last year, Mollie collected 64 pieces of candy while trick or treating. This year her costume is so fabulous that people were ex
never [62]

Answer:

79.6875 % If you can round, please do.

Step-by-step explanation:

5 0
3 years ago
Please help! Show all work.
Morgarella [4.7K]

First, let's work with the denominator alone:

           4⁻⁴ =  1 / 4⁴  =  1/256 .

The original problem is the reciprocal of that  =  256.
8 0
4 years ago
Find the standard deviation of the following data. Round your answer to one decimal place. x 0 1 2 3 4 5 P(X
lbvjy [14]

Answer:

<em></em>\sigma = 1.8<em></em>

<em></em>

Step-by-step explanation:

Given

\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4}& {5} \ \\ P(x) & {0.2} & {0.1} & {0.1} & {0.2} & {0.2}& {0.2} \ \end{array}

Required

The standard deviation

First, calculate the expected value E(x)

E(x) = \sum x * P(x)

So, we have:

E(x) = 0 * 0.2 + 1 * 0.1 + 2 * 0.1 + 3 * 0.2 + 4 * 0.2 + 5  * 0.2

E(x) = 2.7

Next, calculate E(x^2)

E(x^2) = \sum x^2 * P(x)

So, we have:

E(x^2) = 0^2 * 0.2 + 1^2 * 0.1 + 2^2 * 0.1 + 3^2 * 0.2 + 4^2 * 0.2 + 5^2  * 0.2

E(x^2) = 10.5

The standard deviation is:

\sigma = \sqrt{E(x^2) - (E(x))^2}

\sigma = \sqrt{10.5 - 2.7^2}

\sigma = \sqrt{10.5 - 7.29}

\sigma = \sqrt{3.21}

<em></em>\sigma = 1.8<em> --- approximated</em>

5 0
3 years ago
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