All categories

3 years ago

5v– 1/2 =4+ 3/2 v How does one person solve this if the like terms are on opposite sides?

Mathematics

1 answer:

Fofino [41]3 years ago

6 0

Answer:

Step-by-step explanation:

Given

$5v - 1/2 = 4 + 3/2v$

Required

Solve

We have:

$5v - 1/2 = 4 + 3/2v\\$

Collect like terms

$5v - 3/2v = 4 + 1/2$

Express fractions as decimals

$5v - 1.5v = 4 + 0.5$

$3.5v = 4.5$

Make v the subject

$v= \frac{4.5}{3.5}$

Divide by .5

$v= \frac{9}{7}$

You might be interested in

On your own paper graph each system of equations and then describe it: y=x+4 3x+5y=10

ki77a [65]

Each equation form a straight slanting line. For the first equation, it is slanting towards the right which denotes that it has a positive slope. For the the second equation, its plot is slanting towards the left denoting that its slope is negative. Common to both equation is the point (-1.25, 2.75). At this point, the two lines intersect.

7 0

2 years ago

Please help!! Andy is 2 year older than jeff. in 5 years the sum of their ages will be 40 years . find their ages now .... provi

ANTONII [103]

Andy's age = x
Jeff's age = x-2
Andy's age in five years = x+5
Jeff's age in five years = x-2+5
The sum of their ages in five years = x+5 + x-2+5

 x + 5 + x - 2 + 5 = 40
 2x + 8 = 40
 -8 -8
 2x = 32
 :2 :2
 x = 16
x - 2 = 14

Andy is 16 years old and Jeff is 14 years old

8 0

3 years ago

Help me with this geo question plss?!!

denis-greek [22]

Answer:

53.7

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole. On his second stroke, the ball traveled 79 met

Sav [38]

Answer:

0.395 kilometre

Step-by-step explanation:

Given:

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole.

On his second stroke, the ball traveled 79 meters and went into the hole.

Question asked:

How many kilometres from the hole was Martin when he started?

Solution:

Let distance from Martin starting point to the hole in meters = $x$

On Martin's first stroke, ball traveled = $\frac{4}{5} \ of \ total \ distance\ to\ the\ hole$

$=\frac{4}{5} \times x=\frac{4x}{5}$

On his second stroke, the ball traveled and went to the hole = 79 meters

Total distance from starting point to the hole = Ball traveled from first stroke + Ball traveled from second stroke

$x=\frac{4x}{5} +79\\ \\ Subtracting\ both\ sides\ by \ \frac{4x}{5}\\ \\ x- \frac{4x}{5}= \frac{4x}{5}- \frac{4x}{5}+79\\ \\ \frac{5x-4x}{5} =79\\ \\ By \ cross\ multiplication\\ \\ x=79\times5\\ \\ x=395\ meters$