Answer:
16
since it's the least that can be divided by both
Answer:
$324.35
Step-by-step explanation:
249.50x74.80=74.85. markup=add, 74.85+249.50=324.35
I couldn’t figure out d answer to This hope this helped
The sum of the squares of their ages is; 5x²
<h3>How to Solve Algebraic Word Problems?</h3>
We are told that Maria is twice the age of Miriam.
Now, of the age of Miriam is x, then we can say that;
Age of Mariam = x
Age of Maria = 2x
Now, we want to find the sum of the squares of their ages. Thus, this is expressed as;
x² + (2x)²
= x² + 4x²
= 5x²
Read more about Algebraic Word Problems at; brainly.com/question/13818690
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The complete question is;
Express in algebraic language: the sum of the squares of the ages of Maria and Miriam, if it is known that Maria is twice the age of Miriam.
Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
