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insens350 [35]
3 years ago
11

A researcher is interested in whether using your finger to follow the words you are reading changes reading speed. She has stude

nts complete a reading speed test, first without using their fingers to follow the words and then again while using their fingers to follow the words. The researcher randomly selects a sample of 56 students who, at the beginning of the study, scored an average of 256 words per minute on the reading speed test. In the trial where they used their fingers while they read, the students scored an average of 6 words per minute higher. The standard deviation of the difference scores was 29. Since the sample size is larger than 30, the researcher can assume that the sampling distribution of MD is normal. She uses a repeated-measures t test to test that the mean difference is zero, and she describes the results as follows:
In the trial where they used their fingers while they read, the reading speed among students is not significantly different than when they do not use their fingers while they read, t(55) = 1.55, p = 0.127. If the researcher had used a repeated-measures ANOVA to test that the mean reading speed is the same before and after using their fingers while they read, he would describe the results as follows (fill in all missing values): In the trial where they used their fingers while they read, the reading speed among students is different than when they do not use their fingers while they read, F()=, p = 0.127.
Mathematics
1 answer:
serg [7]3 years ago
8 0

Answer:

why are u putting files how do u open it

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3 years ago
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Aleksandr-060686 [28]

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4f

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3 0
4 years ago
Suppose that a sequence is defined as follows. This the 1st four terms of the sequence. ASAP BRANLIEST TY!!​
SashulF [63]

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- 3, 16, - 22, 54

Step-by-step explanation:

Using the recursive formula with a₁ = - 3, then

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Thus

the first 4 terms of the sequence are

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5 0
3 years ago
Part 2: NO LINKS!! NOT MULTIPLE CHOICE! Please help me​
Dmitry_Shevchenko [17]

Answer:

(see attachment for tree diagram)

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

<h3><u>Part (a)</u></h3>

\textsf{P(Head) and P(3)}=\sf \dfrac{1}{2} \times \dfrac{1}{6}=\dfrac{1}{12}

<h3><u>Part (b)</u></h3>

\textsf{P(Tail) and P(even)}=\sf \dfrac{1}{2} \times \dfrac{3}{6}=\dfrac{3}{12}=\dfrac{1}{4}

<h3><u>Part (c)</u></h3>

\textsf{P(not 6)}=\sf 1-\textsf{P(6)}=1-\dfrac{1}{6}=\dfrac{5}{6}

\implies \textsf{P(Head) and P(not 6)}=\sf \dfrac{1}{2} \times \dfrac{5}{6}=\dfrac{5}{12}

<h3><u>Part (d)</u></h3>

As the six-sided die does not have a side labelled "7", the probability of rolling a 7 is zero.

\implies \textsf{P(Head) and P(7)}=\sf \dfrac{1}{2} \times 0=0

7 0
2 years ago
SUSTITUTION 3X-6Y=2<br> 5X+4Y=1
Montano1993 [528]
3x - 6y = 2
5x + 4y = 1

(-1/3, -1/6)

~Hope I helped!~



6 0
3 years ago
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