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REY [17]
3 years ago
14

(9v + 3) + (9v + 1) = ?

Mathematics
1 answer:
Setler [38]3 years ago
6 0

Answer:

18v+4 it's just addition with barriers. imagine that aren't there and it'll be easier.

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At 8am the temperature was 3 degrees below zero by 1 am the temperature rose 14 degrees and by 10 pm dropped 12 degrees what was
Andrews [41]
The temperature was -1°. 3 degrees below 0 is -3 that plus 14 is 11 minus 12 is -1
4 0
4 years ago
The radius of a circle is 18 inches. What is the circle's area?
oksano4ka [1.4K]

Answer:

1017.88 inches

Step-by-step explanation:

Area = πr2 = π x 182 ≈ 1017.87602

3 0
3 years ago
Can someone explain step by step? I’m confused. (Mark for brainliest!)
NikAS [45]

Answer:

190

Step-by-step explanation:

57.5 x 2=115 so that is the arc for CE

then you add that to 55 to get 170

a circle is 360 so then you subtract 360 for 170

6 0
4 years ago
Twice the sum of three and a number is 30. Find the number
DedPeter [7]

9514 1404 393

Answer:

  • 2(x +3) = 30
  • 12

Step-by-step explanation:

When x represents the number, "the sum of 3 and a number" is (x+3). Twice that sum is 2(x+3). "Is 30" means this expression is equal to 30:

  2(x +3) = 30 . . . . an equation for the given conditions

__

We can solve this equation by dividing by 2:

  x + 3 = 15

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The number is 12.

5 0
3 years ago
Solve the equation 2cosA = 3tanA
zavuch27 [327]
\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\\\
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\\\\
-----------------------------\\\\

2cos(A)=3tan(A)\implies 2cos(A)=3\cfrac{sin(A)}{cos(A)}
\\\\\\
2cos^2(A)=3sin(A)\implies 2[1-sin^2(A)]=3sin(A)
\\\\\\
2-2sin^2(A)=3sin(A)\implies 2sin^2(A)+3sin(A)-2

\bf \\\\\\
0=[2sin(A)-1][sin(A)+2]\implies 
\begin{cases}
0=2sin(A)-1\\
1=2sin(A)\\
\frac{1}{2}=sin(A)\\\\
sin^{-1}\left( \frac{1}{2} \right)=\measuredangle A\\\\
\frac{\pi }{6},\frac{5\pi }{6}\\
----------\\
0=sin(A)+2\\
-2=sin(A)
\end{cases}

now, as far as the second case....well, sine of anything is within the range of -1 or 1, so -1 < sin(A) < 1

now, we have -2 = sin(A), which simply is out of range for a valid sine, so there's no angle with such sine

so, only the first case are the valid angles for A
8 0
3 years ago
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