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galina1969 [7]
2 years ago
12

You have a stack of bills with $1 bills and $5 bills in it. you have 43 total bills equaling $99 how many of each type of Bill d

o you have.
Number of $1 bills.
Number of $5 bills
Solve using substitution or elimination show all work
Mathematics
1 answer:
statuscvo [17]2 years ago
5 0

Answer:

<u>29</u> $1 bills and <u>14</u> $5 bills.

Step-by-step explanation:

Let x be the number of $1 bills and y be the number of $5 bills. With the information given, we can set up two equations:

1) x+y=43

2) 1x+5y=99

There are two ways to solve it; with elimination or substitution. In this explanation, I will solve it with elimination.

To solve it with elimination, multiply the first equation by 5 to get:

5x+5y=215

Then, you can subtract the equation we just got by the second equation to get:

4x=116

Thus, x=29. To find y, just substitute x for 29 in the first equation to get:

29+y=43. Therefore, y=14. That means that there are 29 $1 bills and 14 $5 bills. You can check by substituting those values for x and y in either of the first two equations.

Hope this helps :)

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<h3>The option A) x^{10}z^7 is correct answer.</h3><h3>The correct simplification for the given expression \frac{x^{12}\times z^{11}}{x^2\times z^4} is x^{10}z^7</h3>

Step-by-step explanation:

Given expression is x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4th power.

The given expression can be written as \frac{x^{12}\times z^{11}}{x^2\times z^4}

<h3>To choose the correct simplification of the given expression :</h3>

Now we have to simplify the given expression as below

\frac{x^{12}\times z^{11}}{x^2\times z^4}

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