Answer:
(-4)3/(-4)-12
-12/48
-1/4
Step-by-step explanation:
PEMDAS
do multiplication then division
Answer:
log x^13.
Step-by-step explanation:
Using the laws of logarithms
a log b = log b^a and log a + log b = log ab:
3 log x^2 + 7 log x
= log (x^2)^3 + log x^7
= log x^6 + log x^7
= log (x^6*x^7)
= log x^13.
Answer:
16 millimeters
Step-by-step explanation:
- Length of the Triangular Prism=4 millimeters
- Base Length of One Triangular Face=13 millimeters.
- Volume of the Prism =416 cubic millimeters.
Now:
Volume of a Prism=Base Area X Prism Length
Since we have a triangular base:
Volume of the Prism=(0.5 X Base X Height) X Prism Length
Substituting the given values, we obtain:
416=(0.5 X 13 X Height) X 4
416=26 X Height
Divide both sides by 26
Height of its triangular face=16 millimeters
98-70 is 28 meaning that the range is 28
Answer:
(a) 
The expected number in the sample that treats hazardous waste on-site is 0.383.
(b) 
There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Step-by-step explanation:
Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.
N = 209
Only eight of these facilities treated hazardous waste on-site.
r = 8
a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?
n = 10
The expected number in the sample that treats hazardous waste on-site is given by




Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.
b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site
The probability is given by
For the given case, we have
N = 209
n = 10
r = 8
x = 4




Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.