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galina1969 [7]
2 years ago
12

You have a stack of bills with $1 bills and $5 bills in it. you have 43 total bills equaling $99 how many of each type of Bill d

o you have.
Number of $1 bills.
Number of $5 bills
Solve using substitution or elimination show all work
Mathematics
1 answer:
statuscvo [17]2 years ago
5 0

Answer:

<u>29</u> $1 bills and <u>14</u> $5 bills.

Step-by-step explanation:

Let x be the number of $1 bills and y be the number of $5 bills. With the information given, we can set up two equations:

1) x+y=43

2) 1x+5y=99

There are two ways to solve it; with elimination or substitution. In this explanation, I will solve it with elimination.

To solve it with elimination, multiply the first equation by 5 to get:

5x+5y=215

Then, you can subtract the equation we just got by the second equation to get:

4x=116

Thus, x=29. To find y, just substitute x for 29 in the first equation to get:

29+y=43. Therefore, y=14. That means that there are 29 $1 bills and 14 $5 bills. You can check by substituting those values for x and y in either of the first two equations.

Hope this helps :)

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Express 3 log x^2 + 7 log x as a single log
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Answer:

log x^13.

Step-by-step explanation:

Using the laws of logarithms

a log b = log b^a and  log a + log b = log ab:

3 log x^2 + 7 log x

= log (x^2)^3 + log x^7

= log x^6 + log x^7

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8 0
3 years ago
A triangular prism is 4 millimeters long. It has a triangular face with a base of 13 millimeters. The volume of the prism is 416
muminat

Answer:

16 millimeters

Step-by-step explanation:

  • Length of the Triangular Prism=4 millimeters
  • Base Length of One Triangular Face=13 millimeters.
  • Volume of the Prism =416 cubic millimeters.

Now:

Volume of a Prism=Base Area X Prism Length

Since we have a triangular base:

Volume of the Prism=(0.5 X Base X Height) X Prism Length

Substituting the given values, we obtain:

416=(0.5 X 13 X Height) X 4

416=26 X Height

Divide both sides by 26

Height of its triangular face=16 millimeters

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The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr
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Answer:

(a) E(X) =  0.383

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) P(x = 4) = 0.000169

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$ E(X) =  \frac{n \times r}{N} $

$ E(X) =  \frac{10 \times 8}{209} $

$ E(X) =  \frac{80}{209} $

E(X) =  0.383

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$ P(x = 4) =  \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}} $

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$ P(x = 4) =  \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{70 \times 84944276340}{35216131179263320}

P(x = 4) = 0.000169

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0
3 years ago
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