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ZanzabumX [31]
3 years ago
6

The quotient of 5 plus a number d amd negative 2 is 14 (okay so how do I write it as an equation) ​

Mathematics
1 answer:
zalisa [80]3 years ago
8 0

Step-by-step explanation:

We have (5 + d) / (-2) = 14.

=> 5 + d = -28 (multiply both sides by -2)

=> d = -33. (subtract 5 on both sides)

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Step-by-step explanation:

6 0
3 years ago
Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or
WARRIOR [948]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\



\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8

compare them away.
4 0
3 years ago
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