What is the solution to the inequality-8y≤16

Mathematics

2 answers:

777dan777 [17]3 years ago

8 0

The answer is

y ≥ −2

MatroZZZ [7]3 years ago

6 0

The answer is y ≥-2

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Consider the function g that is continuous on the interval [−10, 10] and for which integral from 0 to 10 of g of x times d times

maksim [4K]

The value of the integral $\int\limits^{10}_0 {[g(x) + 2]} \, dx$ given that the integral $\int\limits^{10}_0 {g(x)} \, dx$ = -10, is <u>10</u>.

Finding the area of the curve's undersurface is the process of integration. To do this, cover the area with as many little rectangles as possible, then add up their areas. The total gets closer to a limit that corresponds to the area under a function's curve. Finding an antiderivative of a function is the process of integration. If a function can be integrated and its integral across the domain is finite with the given bounds, then the integration is definite.

In the question, we are given that the function g is continuous on the interval [-10,10] and for which $\int\limits^{10}_0 {g(x)} \, dx$ = -10.

We are asked the value of $\int\limits^{10}_0 {[g(x) + 2]} \, dx$ .

The required value can be found as follows:

$\int\limits^{10}_0 {[g(x) + 2]} \, dx\\\Rightarrow \int\limits^{10}_0 {g(x)} \, dx + \int\limits^{10}_0 {2} \, dx \\\Rightarrow -10 + [2x]_{0}^{10}\\\Rightarrow -10 + [2*10 - 2*0]\\\Rightarrow -10 + 20\\\Rightarrow 10$

Thus, the value of the integral $\int\limits^{10}_0 {[g(x) + 2]} \, dx$ given that the integral $\int\limits^{10}_0 {g(x)} \, dx$ = -10, is <u>10</u>.

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6 0

2 years ago

Read 2 more answers

Help please!(10 points)

podryga [215]

Answer:

Each friend gets 3/4 of a fruit bar

Step-by-step explanation:

8 0