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Marina86 [1]
3 years ago
5

The perimeter of a rectangle is 20 cm. The length of the rectangle is 3 cm less than 2 1/4 times the width. Find the dimensions

of the rectangle
Mathematics
1 answer:
nirvana33 [79]3 years ago
8 0

Answer:

the dimension of the rectangle is 4 cm and 6 cm respectively

Step-by-step explanation:

The computation of the dimension of the rectangle is shown below:

Given that

The perimeter of the rectangle is 20 cm

The width be x

So, the length would be 2 1 ÷ 4 x - 3 i.e.  9 ÷ 4x - 3

Now as we know that

Perimeter of the rectangle = 2 (length + width)

20 = 2 (9 ÷ 4x - 3 + x)

20 = 9 ÷ 2x - 6 + 2x

20 = 4.5x - 6 + 2x

26 = 6.5x

x = 4 cm

Now the length would be

= 9 × 4  ÷ 4  - 3

= 6 cm

Hence, the dimension of the rectangle is 4 cm and 6 cm respectively

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1. Solve for x. Then find the angle measures of the<br>triangle?<br>(4x)<br>(6x+55)<br>(9x+30)​
nalin [4]

Answer:

x =  5.

First angle = 20°,  Second angle = 85°,  Third angle  = 75°

Step-by-step explanation:

The first angle of the triangle  =  (4 x)

The second  angle of the triangle  =  (6x + 55)

The third angle of the triangle  =  (9x + 30)

By ANGLE SUM PROPERTY of a triangle:

First angle + Second  angle +  Third angle  = 180°

⇒ (4 x)  + (6x+55)   +  (9x+30)​  = 180°

or, (4x + 6x + 9x) + ( 55 + 30) =  180°

or, 19x = 180 - 85

or, 19 x  = 95   ⇒ x = 95 /19 = 5

or, x = 5

Hence, first angle of the triangle =  (4 x) = 4 x 5 = 20°

Second angle = ( 6x + 30)  = 6(5) + 55 = 85°

Third angle = (9x  + 30  = 9(5) + 30 = 75°

8 0
3 years ago
g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

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I wish to digitally store a very old book written in an ancient Chinese language. What is the minimum number of megabytes (to th
Alisiya [41]

Answer:

The total number number of megabytes required to store the book is

Step-by-step explanation:

The smallest unit of storage on a computer  are Bits. That is, a single on/off value.

This is different from a Bytes.

Bytes are often represented by the capital letter B, bits by a lower case b.

Please note: A single typed character (for example, 'x' or '8') is stored in one byte.

1 Byte = 8 bits.

1, 000 Bytes = 1 Kilobyte and

1,024 Kilobytes = 1 Megabyte

Therefore 1,000,000 Bytes = 1 Megabyte

STEP I - Get the Number of Bytes required.

Each symbol = 1 byte

Each Page has 445.8 symbols

The book has 360 pages.

Therefore, total number of symbols =

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If our answer has to be in Megabytes, recall that 1,000,000 Bytes = 1 Megabyte.

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In three decimal places our answer therefore is

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Cheers!

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