<u>Answer-</u>
The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

<u>Solution-</u>
Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)
The applying the distance formula,








Two equations are formed because one will be upper from the the given line and other will be below it.
Answer:
solution is (- 3, 5 )
Step-by-step explanation:
given the 2 equations
6x - y = - 23 → (1)
8x + 3y = - 9 → (2)
rearrange (1) expressing y in terms of x
y = 6x + 23 → (3)
Substitute y = 6x + 23 into (2)
8x + 3(6x + 23 ) = - 9
8x + 18x + 69 = - 9
26x + 69 = - 9 ( subtract 69 from both sides )
26x = - 78 ( divide both sides by 26 )
x = - 3
substitute x = - 3 into (3)
y = (6 × - 3 ) + 23 = - 18 + 23 = 5
solution is (- 3, 5 )
Answer:
I think its the answer is B im not sure
Answer:
is the answer.
Step-by-step explanation:
The question has some typo errors.
Rashid and Mikhail submitted a total of x pastries to a baking competition.
Suppose say :
Mikhail made x pastries .
Hence Rashid made
pastries.
And in total they made
pastries.
Now we have that out of x,
of x were brushed with olive oil.
So,
of x that is
are brushed by butter.
So, it becomes 
=
= 
Hence, answer is option B.