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S_A_V [24]
2 years ago
12

At the start of his diet keirin weighted 14 stone 13 pounds three months later he weighted 13 stone 10 pounds. There are 14 poun

ds in a stone
Mathematics
1 answer:
scoundrel [369]2 years ago
8 0

Answer: u need to ask a question

Step-by-step explanation:

could the child have downs syndrome perhaps since it keeps on gaining weight.

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What is the equation of the line passing through the point (4, 5) that is parallel to the line with the equation
Reptile [31]

Answer:

y=2x-3

Step-by-step explanation:

1. find the slope

6x-3y=21

-3y=-6x+21 divide both sides by -3

y=2x-7

slope is 2

2.y-5=2(x-4)

  y-5=2x-8

  y=2x-8+5

  y=2x-3

PARALLEL lines have the same slope

7 0
2 years ago
Simplify the expression (3 - 4i)(1 + 5i) - (2 - i). Show your work please! I have the answer: 21 + `12i but I need to show my wo
masha68 [24]

Answer:

21+12i i hope this will help you

Step-by-step explanation:

(3-4i)(1+5i)-(2-i)

=[3(1+5i)-4i(1+5i)]-(2-i)

=[3+15i-4i-20i²]-(2-i)

=(3+11i-20i²)-(2-i)

opening brackeys

=3+11i-20i²-2+i

=3+11i+1i-20i²-2

as we know that i²=-1

=3-20(-1)-2+12i

=3+20-2+12i

=21+12i

8 0
3 years ago
(02.03) A bicyclist rides 16 miles in 144 minutes. If she continues at this speed, how long will it take her to travel 36 miles?
lubasha [3.4K]
186 miles in that time
7 0
3 years ago
Read 2 more answers
Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
pantera1 [17]

This sequence has generating function

F(x)=\displaystyle\sum_{k\ge0}k^3x^k

(if we include k=0 for a moment)

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k

Take the derivative to get

\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k

\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k

Take the derivative again:

\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k

Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k

so we have

\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

5 0
3 years ago
Please answer the questions
Paladinen [302]
Draw a van diagram then in the middle write what is the same about them. Then state why and how these are the same
5 0
2 years ago
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