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mamaluj [8]
2 years ago
8

A billiard ball starts 86\,\text{cm}86cm86, start text, c, m, end text from the corner pocket, as shown. The ball rolls 120\,\te

xt{cm}120cm120, start text, c, m, end text in another direction, hits a rail, and rolls another 100\, \text{cm}100cm100, start text, c, m, end text into the pocket. What is the angle between the paths before and after the ball hits the rail? Do not round during your calculations. Round your final answer to the nearest degree.
Mathematics
1 answer:
jolli1 [7]2 years ago
4 0

Answer:

45 Degrees

Step-by-step explanation:

Khan Academy

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Show that triangle MPT =Triangle MTP​
exis [7]

Unusual notation.  I won't fuss with it.

a. We have isosceles PRT, so angle  RPT = angle RTP.

By the definition of angle bisector, angle MTP = angle MTF, and angle MPT = angle MPU.

We have m angle RTP = m angle MTF + m angle MTP = 2 m angle MTP

Similarly, m angle RPT = 2 m angle MPT

2 m angle MTP = 2 m angle MPT

angle MPT = angle MPT

That's the first part.

b. That makes MPT isosceles.

c. 2x+124=180

2x = 56

x = 28 degrees

MTP = 28 degrees

d.  We have angle RPT=angle RTP=56 so PRT=180-2(56)=68 degrees

PUT = 180 - UTP - UPT = 180 - 28 - 56 = 96 degrees

Bad drawing, PUT looks acute.

angle PRT = 68 degrees, angle PUT = 96 degrees

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Answer:

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Step-by-step explanation:

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