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3 years ago

There is no solution to the following system of equations.

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

6 0

Answer:

True

Step-by-step explanation:

We are given that system of equation

x<3

y>3

We have to find that there is no solution of system of equation is true or not.

First we change inequality equation into equality equation

x=3

y=3

When x=0

0<3

It is true equation therefore, the shaded region towards the origin.

When y=0

0>3

It is false equation. Therefore, the shaded region above the origin.

From the graph

There is no solution of system of equation.

Hence, option true is correct.

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You have 2000 grams of substance A which has decay constant 0.03, and you have 3000 grams of substance B, which has decay consta

joja [24]

Answer:

If you have a quantity X of a substance, with a decay constant r, then the equation that tells you the amount of substance that you have, at a time t, is:

C(t) = X*e^(-r*t)

Now, we know that:

We have 2000g of substance A, and it has a decay constant of 0.03 (i assume that is in 1/year because the question asks in years)

And we have 3000 grams of substance B, with a decay constant of 0.05.

Then the equations for both of them will be:

Ca = 2000g*e^(-0.03*t)

Cb = 3000g*e^(-0.05*t)

Where t is in years.

We want to find the value of t such that Ca = Cb.

So we need to solve:

2000g*e^(-0.03*t) = 3000g*e^(-0.05*t)

e^(-0.03*t) = (3/2)e^(-0.05*t)

e^(-0.03*t)/e^(-0.05*t) = 3/2

e^(t*(0.05 - 0.03)) = 3/2

e^(t*0.02) = 3/2

Now we can apply Ln(x) to both sides, and get:

Ln(e^(t*0.02)) = Ln(3/2)

t*0.02 = Ln(3/2)

t = Ln(3/2)/0.02 = 20.3

Then after 20.3 years, both substances will have the same mass.

6 0

3 years ago

HELP With this question

ahrayia [7]

Answer:

Step-by-step explanation:

sin 60=CB/18

$\frac{\sqrt{3} }{2} =\frac{CB}{18} \\CB=9\sqrt{3}$

6 0

3 years ago

Information about the proportion of a sample that agrees with a certain statement is given below. Use StatKey or other technolog

lorasvet [3.4K]

Answer:

a) Standard Error = 0.010

b) 95% Confidence Interval = (0.0924 , 0.1316)

Step-by-step explanation:

a) The formula for Standard Error = √Sample Proportion (1 - sample proportion)/n

Standard Error = √p (1 - p)/n

We are told in the question that:

In a random sample of 400 people, 112 agree and 288 disagree. Estimate the standard error using 1000 samples

p = x/n

n = 1000 because we were told to use it instead of 400

x = number for people that agree = 112

p = 112/1000

p = 0.112

Standard Error = √p (1 - p)/n

= √0.112 (1 - 0.112)/1000

= √0.112 × 0.888/1000

= √0.099456 /1000

= √0.000099456

= 0.0099727629

Approximately to 3 decimal places = 0.010

Therefore, the standard error is 0.010

b) The Question above also asked that we solve for the 95% Confidence Interval

The formula =

p ± z × Standard Error

p = 0.112

z score for 95% confidence interval = 1.96

Standard Error = 0.010

Confidence Interval =

0.112 ± 1.96 × 0.010

= 0.112 ± 0.0196

0.112 - 0.0196

= 0.0924

0.112 + 0.0196

0.1316

Therefore, the 95% confidence interval = (0.0924 , 0.1316)

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