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Alekssandra [29.7K]
3 years ago
11

A jar of marbles contains the following: two red marbles, three white marbles, five blue marbles, and one green marble.

Mathematics
1 answer:
Lady_Fox [76]3 years ago
3 0

Answer:

5/11

Step-by-step explanation:

5 blue marbles and 11 total marbles

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8. Charlotte is given the equation 3x - 4y = 12. She needs to create a graph of the equation, but
Zielflug [23.3K]

Answer/Step-by-step explanation:

Note:

<u>Graphing From An Equation: </u>

Equation are frequently written in slope-intercept form { y = mx+b}.

Which "m" represents the slope and "b" represents the y-intercept.

<u>Solutions and Equation:</u>

Solutions to linear equations contain any points located on the graphed line.

Ordered Pair = Solution to an equation if it's values are substituted in the equation which makes it true

Solve:

{x = 0 }       3(0) - 4y = 12

                       -4y = 12                                 (0, -3 )

                       -4y/-4 = 12/-4

                                y = -3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

{y = 0}                  3x-4(0) =12

                                3x = 12              (4,0)

                                 3x/3 = 12/3

                                        x = 4

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

<u><em>~Lenvy~</em></u>

5 0
2 years ago
While completing a multiplication problem I need to know how to do it by associative
Vera_Pavlovna [14]

Associative property Says that you can add or multiply regardless of how the numbers are group

3 0
3 years ago
Evaluate f(t)=-2t2+ 1 for f(-3).
podryga [215]

Answer:

7

Step-by-step explanation:

First, plug-in f(-3) into t in the function:

f(-3)=-2(-3) +1

Second, multiply -2 and -3 to get 6:

f(-3)=-2(-3)+1⇒f(-3)=6+1

Third, add 6 and 1 to get your answer:

f(-3)= 6+1⇒f(-3)=7

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3 years ago
If someone covers 4 laps in 12 minutes what was the speed?
Alisiya [41]
If someone covers 4 laps in 12 minutes, he would be able to cover 1 lap in 3 minutes if that was the question. The question isn’t really clear.
3 0
3 years ago
use the information provided to write the standard form equation of each hyperbola vertices:(4,14), (4,-10) foci: (4,15), (4,-11
Evgen [1.6K]
So... if you notice the picture below, based on the given vertices, is a hyperbola with a vertical traverse axis

meaning for the equation, the fraction with the "y" variable is the positive fraction, thus \bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1

so... what' the point h,k for the center?  well, just take a peek at the graph, the center is half-way between both vertices, that's h,k

what's the "a" component or the traverse axis... well, is the distance from one vertex to the center, notice the picture, notice how many units from either vertex to the center, that's "a"

now.. what's "b"?  well, "b" comes from the conjugate axis, or the other runnning over the x-axis   hmm the smaller one in this case.... well, we dunno what "b" is

however, we know the distance from either focus, to the center of the hyperbola, and that distance "c", is  \bf c=\sqrt{a^2+b^2}

notice the picture, notice the distance from either focus to the center, that's the distance "c", thus  \bf c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b

that'd be "b"

bearing in mind that   \bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1&#10;\qquad &#10;\begin{cases}&#10;center= ({{ h}},{{ k}})\\\\ b=\sqrt{c^2-a^2}&#10;\end{cases}

8 0
3 years ago
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