$f(x)=x^2+3 \\ g(x)= -x-1 \\ 1. (g+f)(2)=g(2)+f(2)=(-x-1)+ (x^{2} +3)= x^{2} -x+2= (2)^{2} -(2)+2=4 \\ 2. (f/g)(1)=\frac{f(1)}{g(1)}= \frac{x^2+3}{-x-1} = \frac{(1)^2+3}{-(1)-1} = \frac{4}{-2} =-2$
$3. (g-f)(6) =g(6)-f(6)=(-x-1)-( x^{2} +3)=- x^{2} -x-4 \\ =- (6)^{2} -(6)-4=-46$

4 0

3 years ago

||25 POINTS WILL GIVE BRAINLIEST||

Harrizon [31]

Answer:

Step-by-step explanation:

-1+(-6)

6 0

3 years ago

Read 2 more answers

Translate the following statement into an equation and solve for x

Tamiku [17]

Answer:

104 = -13 x -8

Step-by-step explanation:

The reason you got it wrong is, I'm assuming, because of the way you formatted it. Try this and see if it works.

3 0

3 years ago