Answer:
Diamond is the hardest mineral
Explanation:
mohs scale has been used worldwide to test the hardness of a mineral.Because it is cheap,easy to do and understood instantly. Other hardness test never gain that much popularity as Mohs scale.Its a relative integer scale comparison of being scratched. Other hardness test in which a specific pressure applied for a specific length of time.An example of a mineral with variable hardness is kaynte. Another best example is diamond with variable hardness people who cut diamond have known its variable hardness, In Mohs scale of hardness diamond 's position is number 10-10000 is its hardness.
Answer:
Animal waste decay by the action of bacteria which create :
- Ammonia and nitrate products i.e. rich in nitrogen.
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Answer:
a. Two of these are correct.
Explanation:
The two correct options are
b. Is a critical component or requirement for wound healing to take place
d. Existing blood vessels give rise or sprout to form new blood vessels
Angiogenesis is the physiological means in which new blood vessels form pre-existing vessels, developed in the starting phases of vasculogenesis. Angiogenesis is a usual and important process in growth and development, wound healing and in the development of granulation tissue.
The growth and maturation of blood vessels is a largely regulated multistep mechanism called angiogenesis.
The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because<u> fructose 1,6-bisphosphate can undergo no other reactions than those of glycolysis.</u>
<h3>
What is phosphorylation?</h3>
- The crucial process of glycolysis involves the breakdown of glucose into two molecules of pyruvate. It involves a number of steps and many enzymes.
- It takes place over the course of ten phases, demonstrating how important and crucial phosphorylation is to the production of the final goods. Step 1 of the preliminary step (first half of glycolysis) and step 6 of the payout phase reactions are started by phosphorylation (second phase of glycolysis).
- Because fructose-6-phosphate cannot cross the cell membrane, it is forced to remain inside the cell. Step 3 involves phosphorylation, when fructose-6-phosphate is changed into fructose-1,6-bisphosphate.
To learn more about phosphorylation with the given link
brainly.com/question/15585148
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<span>Deoxyribose is the same as ribose, except that the former has one more OH. DNAand RNA is the sugar, with 2-deoxyribose being replaced by the alternative pentosesugar ribose in RNA. The four bases found in DNA are adenine (abbreviated A), cytosine (C), guanine (G) and thymine (T).</span>
