A photograph measures 4 inches wide and 5 inches long if you have the photograph in large to fit a frame 36 inches long what is
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
Let . We have that
if and only if we can find scalars
such that
. This can be translated to the following equations:
1.
2.
3.
Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for and check if the third equationd is fulfilled.
Case (2,6,6)
Using equations 1 and 2 we get
whose unique solutions are , but note that for this values, the third equation doesn't hold (3+2 = 5
6). So this vector is not in the generated space of u and v.
Case (-9,-2,5)
Using equations 1 and 2 we get
whose unique solutions are . Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.
The tower is 61.65 meters tall.
<u>SOLUTION: </u>
Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.
At the same time, a nearby tower casts a shadow that is 36.25 m long.
We have to find height of the tower.
Now, we know that,
Then, (let it be) n meter tall 36.25 long shadow
So, by cross multiplication method,
This can be written as,
Cross multiplications steps: (To find Single Variable)
- Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
- Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
- Set the two products equal to each other.
- Solve for the variable.