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Simora [160]
3 years ago
13

The publisher considered 10 manuscripts for publication and accepted 3. What percent were rejected?

Mathematics
2 answers:
Lesechka [4]3 years ago
6 0

Answer:

70%

Step-by-step explanation:

First find the number that were rejected

10-3 = 7

Then take that over the total

7/10

.7

70%

natka813 [3]3 years ago
4 0

Answer: 70%

Step-by-step explanation:

10 - 3 = 7

So, there are 7 manuscripts that are rejected.

7/10 are rejected.

70/100

Therefore, 70% are rejected.

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Taking y=y(x) and differentiating both sides with respect to x yields

\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0

Solving for the first derivative, we have

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x}y

Differentiating again gives

\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0

Solving for the second derivative, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{3+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}y=-\dfrac{3+\frac{9x^2}{y^2}}y=-\dfrac{3y^2+9x^2}{y^3}

Now, when x=1 and y=2, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}\bigg|_{x=1,y=2}=-\dfrac{3\cdot2^2+9\cdot1^2}{2^3}=\dfrac{21}8\approx2.63
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The volume, V, of a cylinder is equal to this area base, B, times it’s height h. The diameter of a cylinder is 18 feet and its h
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Answer:

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Answer:

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Step-by-step explanation:

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