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4 years ago

1.What is the correct reason for statement 2?

1 answer:

7 0

1. The reason for statement 2 is
Distributive Property

2. The reason for statement 2 is
Commutative Property

3. The reason for statement 3 is
Associative Property

4. The reason for statement 5 is
Commutative Property

5. The reason for statement 1 is
Associative Property
The reason for statement 3 is
Addition

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The frequency of vibration of a piano string varies directly as the square root of the tension on the string and inversely as th

artcher [175]

Answer:

about 409.946 Hz

Step-by-step explanation:

The multiplier of frequency is (√(tension multiplier))/(length multiplier), so is ...

(√1.25)/1.2 = (5/12)√5 ≈ 0.931695

So, the longer, tighter string will have the lower frequency of about ...

0.931695×440 Hz ≈ 409.946 Hz

8 0

3 years ago

Seis manzanas y 8 peras cuestan $26. ¿Cuanto cuesta cada pera y cada manzana sabiendo que cada manzana cuesta el triple de lo qu

Rom4ik [11]

Usando un sistema de ecuaciones, se encuentra que

Cada manzana cuesta $3.
Cada pera cuesta $1.

-----------------------

Un sistema de ecuaciones soluciona esta pergunta.
El custo de una manzana es x.
El custo de una pera es y.

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Seis manzanas y 8 peras cuestan $26, o sea, $6x + 8y = 26$
Cada manzana cuesta el triple de cada pera, o sea, $x = 3y$

-----------------------

Primero, encontramos el cuesto de una pera, substituyendo la segunda en la primera ecuación.

$6x + 8y = 26$

$6(3y) + 8y = 26$

$18y + 8y = 26$

$26y = 26$

$y = \frac{26}{26}$

$y = 1$

Cada pera cuesta $1.

-----------------------

Cada manzana cuesta el triple de cada pera, o sea, $x = 3y = 3(1) = 3$ .

Cada manzana cuesta $3.

Se encuentra um problema similar en brainly.com/question/24646137

6 0

3 years ago

A random sample of the actual weight of 5-lb bags of mulch produces a mean of 4.963 lb and a standard deviation of 0.067 lb. If

dsp73

Answer: B) 4.963±0.019.

Step-by-step explanation:

Confidence interval for population mean ( when population standard deviation is not given) is given by :-

$\overline{x}\pm t^*\dfrac{s}{\sqrt{n}}$

, where $\overline{x}$ = Sample mean

n= Sample size

s= sample standard deviation

t* = critical t-value.

As per given:

n= 50

Degree of freedom = n-1 =49

$\overline{x}= 4.963\ lb$

s= 0.067 lb

For df = 49 and significance level of 0.05 , the critical two-tailed t-value ( from t-distribution table) is 2.010.

Now , substitute all values in the formula , we get

$4.963\pm (2.010)\dfrac{0.067}{\sqrt{50}}\\\\ 4.963\pm (2.010)(0.0094752)\\\\ 4.963\pm0.019045152\approx4.963\pm0.019$

Hence, a 95% confidence interval for the mean weight (in pounds) of the mulch produced by this company is $4.963\pm0.019$ .

Thus , the correct answer is B) 4.963±0.019.

7 0

3 years ago

In a recent survey 75 of the community favored building a police substation in their neighborlhood. If 20 citizens are chosen. W

Anton [14]

Answer:

Mean = 15

Standard deviation = 1.94

Step-by-step explanation:

We are given the following information:

We treat favoring of building a police substation as a success.

P(Success) = 75% = 0.75

Then the number of citizens follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 20

We have to find the mean and the standard deviation.

$\mu = np = 20(0.75 ) = 15\\\sigma = \sqrt{np(1-p)} = \sqrt{20(0.75)(1-0.75)} = 1.94$

Thus, the mean of favoring the substation is 15 and the standard deviation of favoring substation is 1.94

7 0

3 years ago

The students at Rudy's school voted between a bear and a lion as the new school mascot. 14 students voted for the bear and 86 st

tino4ka555 [31]

Answer:

14%

Step-by-step explanation:

Given :

Bear voters = 14

Lion voters = 86

Percentage of students who voted bear :

(Bear voters / total number of Voters) * 100%

Total number of voters = (bear voters + lion voters) = (14 + 86) = 100

Percentage of students who voted bear :

(14 / 100) * 100%

0.14 * 100%

= 14%

5 0

3 years ago