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LenKa [72]
2 years ago
6

This is the question

Mathematics
2 answers:
mina [271]2 years ago
7 0

Answer:

the answer is x = 3, but i gave you the explanation to figure it out on your own.

Step-by-step explanation:

x = 3

27 + 5/8 = 32

vesna_86 [32]2 years ago
6 0

Answer:

x= 3

Step-by-step explanation

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Identify the 33rd term of the arithmetic sequence 9, 7 and one half, 6...
marta [7]

Answer:

  -39

Step-by-step explanation:

The general term of an arithmetic sequence is ...

  an = a1 +d(n -1)

This sequence has first term a1=9 and common difference d=(7.5-9) = -1.5. Then the 33rd term is ...

  a33 = 9 -1.5(33 -1) = 9 -48 = -39

The 33rd term is -39.

5 0
3 years ago
What is the perimeter of a triangle that has side measures of the following
defon
I got 3x^2 + 12x + 4. I recommend you verify my answer, so you have to combine like terms in the first expression then add all the expressions.
8 0
2 years ago
What percent of 200 is 16?,,,,
Zina [86]

Answer:

8%

Step-by-step explanation:

To find the percent, divide 16 by 200, then multiply it by 100.

(16 / 200) x 100

0.08 x 100

= 8

So, 16 is 8% of 200

8 0
3 years ago
Read 2 more answers
What answer i need fast
irina [24]

2/3 cup pineapple for every 1/3 cup OJ

 there are three 1/3 cups in 1 cup

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5 0
2 years ago
Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4
arsen [322]

we are given

R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k

now, we can find x , y and z components

x=cos(8t),y=sin(8t),z=8ln(cos(t))

Arc length calculation:

we can use formula

L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt

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now, we can plug these values

L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt

now, we can simplify it

L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8sec(t) dt

now, we can solve integral

\int \:8\sec \left(t\right)dt

=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|

now, we can plug bounds

and we get

=8\ln \left(\sqrt{2}+1\right)-0

so,

L=8\ln \left(1+\sqrt{2}\right)..............Answer

5 0
2 years ago
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