16 - 4 [ 3 + 2 / (9 - 7)]
16 - 4 [ 3 + 2 / 2)]
16 - 4 [ 3 + 1 ]
16 - 4 [4]
16 - 16
0 <===
I think its A not sure though
To find the 'maximum height' we will need to take the derivative of h(t) = –16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.
Answer:
B
Step-by-step explanation:
You can just move upper y equation and it will be:
6x+3(3x-5)=15
6x+9x-15=15
15x-15=15
15x=30
x=2
