Help plxxxx thank you

If f (x) = x + 7 and g (x) = StartFraction 1 Over x minus 13 EndFraction, what is the domain of (f circle g) (x)?

Rashid [163]

Answer:

R-{13}

Step-by-step explanation:

We are given that

$f(x)=x+7$

$g(x)=\frac{1}{x-13}$

We have to find the domain of fog(x).

$fog(x)=f(g(x))$

$fog(x)=f(\frac{1}{x-13})$

$fog(x)=\frac{1}{x-13}+7=\frac{1+7x-91}{x-13}=\frac{7x-90}{x-13}$

Domain of f(x)=R

Because it is linear function.

Domain of g(x)=R-{13}

Because the g(x) is not defined at x=13

fog(x) is not defined at x=13

Therefore, domain of fog(x)=R-{13}

6 0

2 years ago

Read 2 more answers

Solve: 48 > -6x please help me ill give 15 points!

Leya [2.2K]

Answer:

Inequality Form: x < − 16

Interval Notation: ( − 8 , − 16 )

5 0

3 years ago

I need the answers to it please. I'll give 36 points

nadya68 [22]

1st question

make line plot similar to the second. above 1/6 put 6 x's; above 1/3 put 3 x's; above 1/2 put 6 x's.

average: 1/3

7 0

3 years ago

Question in image ddddddddddddddddd

Kisachek [45]

Step-by-step explanation:

"congruent" for lines simply means they are equally long.

15. yes. AB = EF = 3

16. yes. BD = DF = 8

17. no. AC = 5, CD = 6

18. yes. AC = DE = 5

19. no. BE = 13, CF = 14

20. no. CD = 6, DF = 8

3 0

7 months ago

A club is choosing 2 members to serve on a committee. The club has nominated 2 women and 4 men. Based on chance alone, what is t

tekilochka [14]

Answer:

53.33% probability that one woman and one man will be chosen to be on the committee

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the members are chosen is not important, so we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

What is the probability that one woman and one man will be chosen to be on the committee?

Desired outcomes:

One woman, from a set of 2, and one man, from a set of 4. So

$D = C_{2,1}*C_{4,1} = \frac{2!}{1!1!}*\frac{4!}{1!3!} = 8$

Total outcomes:

Two members from a set of 2 + 4 = 6. So

$T = C_{6,2} = \frac{6!}{2!4!} = 15$

Probability:

$p = \frac{D}{T} = \frac{8}{15} = 0.5333$

53.33% probability that one woman and one man will be chosen to be on the committee

5 0

2 years ago