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3 years ago

3. A university issued 3,007 parking

Mathematics

1 answer:

ipn [44]3 years ago

5 0

Answer:

218

Step-by-step explanation:

No. of permits issued in one year= 3,007

no. of permits issued in year two= 2,789

no. of permits more in first than second= first year permits - second year permits

ie,

3,007-2,789 = 218

therefore,

there were 218 permits more in the first year #answerwithquality #BAL

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Using the order of operations, what would be the first step:<br><br> 4−8÷1−3[3+(7−5)2]

jeka94

Answer:

(7-5)

Step-by-step explanation:

According to PEMDAS, parenthesis go first. But there are two sets of parenthesis so the one inside the other goes first.

Next would be [3+(2*2)]

Then, [3+4]

Then, -8/1

Then, -3(7)

So the question would be 4-8-21

Which gives you -25 as an answer.

I realize that you weren't asking for the whole thing but maybe there are follow up questions.

3 0

3 years ago

Desmond measured a city park and made a scale drawing. The scale he used was 1 centimeter: 9 meters. The actual width of the soc

kupik [55]

Answer:

6 cm

Step-by-step explanation:

1 cm : 9 meters --> 1cm/9m

? cm : 54 meters --> ?cm/54m

$\frac{1}{9}=\frac{?}{54}; 54*\frac{1}{9}=?;6=?$

7 0

3 years ago

A swimming pool with a volume of 30,000 liters originally contains water that is 0.01% chlorine (i.e. it contains 0.1 mL of chlo

SpyIntel [72]

Answer:

$R_{in}=0.2\dfrac{mL}{min}$

$C(t)=\dfrac{A(t)}{30000}$

$R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}$

$A(t)=300+2700e^{-\dfrac{t}{1500}},$ A(0)=3000$

Step-by-step explanation:

The volume of the swimming pool = 30,000 liters

(a) Amount of chlorine initially in the tank.

It originally contains water that is 0.01% chlorine.

0.01% of 30000=3000 mL of chlorine per liter

A(0)= 3000 mL of chlorine per liter

(b) Rate at which the chlorine is entering the pool.

City water containing 0.001%(0.01 mL of chlorine per liter) chlorine is pumped into the pool at a rate of 20 liters/min.

$R_{in}=$ (concentration of chlorine in inflow)(input rate of the water)

$=(0.01\dfrac{mL}{liter}) (20\dfrac{liter}{min})\\R_{in}=0.2\dfrac{mL}{min}$

Volume of the pool =30,000 Liter

$Concentration, C(t)= \dfrac{Amount}{Volume}\\C(t)=\dfrac{A(t)}{30000}$

(d) Rate at which the chlorine is leaving the pool

$R_{out}=$ (concentration of chlorine in outflow)(output rate of the water)

$= (\dfrac{A(t)}{30000})(20\dfrac{liter}{min})\\R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}$

(e) Differential equation representing the rate at which the amount of sugar in the tank is changing at time t.

$\dfrac{dA}{dt}=R_{in}-R_{out}\\\dfrac{dA}{dt}=0.2- \dfrac{A(t)}{1500}$

We then solve the resulting differential equation by separation of variables.

$\dfrac{dA}{dt}+\dfrac{A}{1500}=0.2\\$The integrating factor: e^{\int \frac{1}{1500}dt} =e^{\frac{t}{1500}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{1500}}+\dfrac{A}{1500}e^{\frac{t}{1500}}=0.2e^{\frac{t}{1500}}\\(Ae^{\frac{t}{1500}})'=0.2e^{\frac{t}{1500}}$

Taking the integral of both sides

$\int(Ae^{\frac{t}{1500}})'=\int 0.2e^{\frac{t}{1500}} dt\\Ae^{\frac{t}{1500}}=0.2*1500e^{\frac{t}{1500}}+C, $(C a constant of integration)\\Ae^{\frac{t}{1500}}=300e^{\frac{t}{1500}}+C\\$Divide all through by e^{\frac{t}{1500}}\\A(t)=300+Ce^{-\frac{t}{1500}}$

Recall that when t=0, A(t)=3000 (our initial condition)

$3000=300+Ce^{0}\\C=2700\\$Therefore:\\A(t)=300+2700e^{-\dfrac{t}{1500}}$

3 0

3 years ago

Henry is 4 years younger than Linda. Linda is 20 years old. After correctly carrying out the Solve step of the five-step problem

Troyanec [42]

L = 20
H = L - 4
H = 20 - 4
H = 16
Hope this helps

5 0

3 years ago

Read 2 more answers

Help please! and explain if you can

EleoNora [17]

Answer:

4) y = 9

5) x = -1

6) y = -5x − 9

Step-by-step explanation:

4) x = 3 is a vertical line with an x-intercept of (3, 0). It has an undefined slope.

A perpendicular line to that will be y = a, which is a horizontal line with a y-intercept of (0, a) and a slope of 0. Since this line passes through (3, 9), the equation of the line must be y = 9.

5) The y-axis is x = 0. A parallel line that includes the point (-1, -2) is x = -1.

6) Parallel lines have the same slope, so:

y = -5x + b

To find the value of b (the y-intercept), plug in the point (-2, 1):

1 = -5(-2) + b

1 = 10 + b

b = -9

y = -5x − 9

3 0

3 years ago