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drek231 [11]
3 years ago
9

Find the value of x and y​

Mathematics
1 answer:
sergeinik [125]3 years ago
5 0

Therefore, x= 108° and y =42°

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Plsssssssss help!!!!!!!!!!!!!!!!!
ss7ja [257]

Answer:

C) ∠LMO = 50°

Step-by-step explanation:

When you add the degrees of all the angles in a triangle, you get 180, so...

180 = 60 + 70 + x

180 - 60 - 70 = x

x = 50

4 0
3 years ago
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Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
4 years ago
Solve.<br> {y= 2x – 6<br> {4x – 2y = 14<br> Use the substitution method
Colt1911 [192]

Answer:

No Solution

Step-by-step explanation:

5 0
3 years ago
What is another way to write 42 + 63
satela [25.4K]
You could write this  by going 63+42 or add 63 and 42 
hope that's what you are looking for ;-)<span />
7 0
3 years ago
Read 2 more answers
Can someone help me please
Ostrovityanka [42]

Answer:

D

Step-by-step explanation:

as we can easily see, the x-coordinates of all points increased by 7.

so, we need a solution with "x+7". that eliminates B and C.

with that transition (glide) the triangle moved to the right into the 4th quadrant.

and now, as a second step, it needs to move up, above the x-axis, into the 1st quadrant.

and that is a reflection across the x-axis.

a reflection across the y axis would bring it back into the 3rd quadrant, where it started.

so, it is D.

6 0
2 years ago
Read 2 more answers
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