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Digiron [165]
3 years ago
6

A telecommunications company offers two calling cards. The first card costs $25 for 750 minutes, while the second card costs $40

for 1,300 minutes. Which is the better deal?
$ ? for ? minutes is the better deal.
Mathematics
1 answer:
dmitriy555 [2]3 years ago
4 0

Step-by-step explanation:

You can use the unituary method in this one

First card:

$25/750 min

divide both sides by 750 to figure out how many $ per min the calling card would be

25/750=0.033333333333333333333333333333333333333

750/750=1

the first card costs $0.03333333(going on)/min

Second card

$40/1,300 min

Divide both sides by 1,300

40/1300=0.03076923

1300/1300=1

Second card costs $0.03076923/min

$0.03076923<$0.03333333(going on)

therefore the second card is the better deal

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Step-by-step explanation:

Solution:

It is given that, Universal set is the set of all Natural Numbers.

and

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D = {x:x ∈ N and x > 10} = {1,2,3,4,5,6,7,8,9}

U = {1,2,3,4,5,6,7,8,9,10,11,........}

Complements:

A^{'} = U-A = {1,2,3,4,5,6,7,8,9,10,11,........} - {2,4,6,8,10,.....}

A^{'} = {1,3,5,7,9,....}

B^{'} = U-B =  {1,2,3,4,5,6,7,8,9,10,11,........} - {3,6,9,12,15,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = U-C = {1,2,3,4,5,6,7,8,9,10,11,........} - {6,7,8,9,10,.....}

C^{'} = {1,2,3,4,5}

D^{'} = {1,2,3,4,5,6,7,8,9,10,11,........} - {1,2,3,4,5,6,7,8,9}

D^{'} = {10,11,12,13,14,15,......}

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