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2 years ago

Find c. Round to the nearest tenth

Mathematics

1 answer:

sergeinik [125]2 years ago

8 0

Answer:

c = <u>0.5 cm</u>

Step-by-step explanation:

Using the Sine rule in the triangle, then

= ( cross- multiply )

c × sin105° = 2 × sin15° ( divide both sides by sin105°

c = ≈ 0.5 cm ( to the nearest tenth )

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See the image attached for all information needed.

avanturin [10]

Answer:

12.54 square miles

Step-by-step explanation:

Area of Parallelogram = Base x Height

In this case, Base = 3.3 mi and Height = 3.8 mi

Hence,

Area = 3.3 x 3.8 = 12.54 square miles

6 0

2 years ago

Read 2 more answers

I need some help here

grandymaker [24]

In 1 and 2, you are asked to find "a" and "b" in the pattern
g(x) = a•bˣ

1: selection 2
2: selection 4

3. You want the result of evaluating 4000*(1.06)⁵ ≈ 5352.90, selection 2.

3 0

3 years ago

How many 6 ounce cups can be filled from 4 gallons of juice

Lera25 [3.4K]

6x4 is the anwser because since there are 6 ounces so you got to multiply 6x4 which is 24

3 0

3 years ago

In a group of 60 students, 18 students take Algebra I, 20 students take Algebra II, and 10 students take both subjects. How many

frosja888 [35]

Your answer is B. 12.

12 kids are unaccounted for after you subtract the kids that take A1, then A2, the both subjects.

6 0

3 years ago

Solve square root of x + square root of x+2 = 2

andrew-mc [135]

The value of x is $\frac{1}{4}$

Step-by-step explanation:

Given:

$\sqrt{x} + \sqrt{x + 2} = 2$

Rearranging the radical on left side,

$\sqrt{x + 2} = 2 - \sqrt{x}$

Power on both sides,

$(\sqrt{x + 2})^{2} = (2 - \sqrt{x})^{2}$

Simplifying the left,

$x + 2 = (2 - \sqrt{x} )^{2}$

For the RHS equation, use the property of (a-b)² = (a²-2ab+b²),

$= > x + 2 = {2}^{2} - (2 \times 2 \sqrt{x}) + ( \sqrt{x})^{2}$

Now calculating its powers,

$= > x + 2 = 4 - 4\sqrt{x} + x$

Now sending -4√x to the LHS (left side), its sign becomes plus (+),

$= > 4 \sqrt{x} = 4 + x - x - 2$

Now the +x and -x will be cancelled,

$= > 4 \sqrt{x} = 4 - 2$

$= > 4 \sqrt{x} = 2$

Bringing 4 to the right side, it becomes the denominator,

$= > \sqrt{x} = \frac{2}{4}$

$= > \sqrt{x} = \frac{1}{4}$

Now powering both sides,

$= > ( \sqrt{x})^{2} = ( \frac{1}{2})^{2}$

$= > x = \frac{1}{4}$

4 0

2 years ago