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3 years ago

Please help with this question

Mathematics

1 answer:

Rufina [12.5K]3 years ago

5 0

Answer:

im not too sure but try using a cartesuan plane and measure it precisely using a protractor then key in the measurements. Im not entirely sure its the correct method tho

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Solve the following linear quadratic system of equations algebraically. y=^2+3x-2 y+3=5x

USPshnik [31]

Answer:

$x=1$

$y=2$

Step-by-step explanation:

$y=x^2+3x-2$ , $y+3=5x$

Replace all occurrences of $y$ in $y+3=5x$ with $x^2+3x-2.$

$(x^2+3x-2)+3=5x$

$y=x^2+3x-2$

Add $-2$ and 3.

$x^2+3x+1=5x$

$y=x^2+3x-2$

Subtract 5x from both sides of the equation.

$x^2+3x+1-5x=0$

$y=x^2+3x-2$

Subtract 5x from 3x.

$x^2-2x+1=0$

$y=x^2+3x-2$

Rewrite 1 as $1^2$ .

$x^2-2x+1^2=0$

$y=x^2+3x-2$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$2x=2$ · $x$ · $1$

$y=x^2+3x-2$

Rewrite the polynomial.

$x^2-2$ · $x$ · $1$ $+$ $1^2=0$

$y=x^2+3x-2$

Factor using the perfect square

trinomial rule $a^2-2ab+b^2=(a-b)^2,$

where a = x and b = 1.

$(x-1)^2=0$

$y=x^2+3x-2$

Set the $x-1$ equal to 0.

$x-1=0$

$y=x^2+3x-2$

Add 1 to both sides of the equation.

$x=1$

$y=x^2+3x-2$

Replace all occurrences of $x$ in

$y=x^2+3x-2$ with 1.

$y=(1)^2+3(1)-2$

$x=1$

$y=2$

3 0

3 years ago

Hey can you please help me posted picture of question

belka [17]

The graph is crossing the x-axis at x = - 4 .

If you observe the graph it is touching x = -4 and turning away. When graph exhibit such a behavior we say that the multiplicity of the root is 2. This means the root x = -4 occurs two times. So the factors of the polynomial are x + 4 and x + 4

So the given polynomial can be expressed as (x+4)(x+4).

Thus, the correct answer is option A

4 0

4 years ago

Evaluate the following rational equations below, and identify which rational equation is transformable to a quadratic equation.

ladessa [460]

Answer:

2m^2 + 14m - 81 = 0

Step-by-step explanation:

It looks like

(m + 7)/9 = 18/4m

Cross-multiplication:

4m(m+7) = 9*18
2m(m+7) = 9*9
2m^2 + 14m = 81
2m^2 + 14m - 81 = 0

Here is the quadratic equation

7 0

3 years ago

What is the simplified form of expression c^9d^ -7/c^14 d^-10

devlian [24]

You subtract c^9 - c^14 and you get c^5
then you subtract d^-7 - d^-10 and you get d^3 because negative and a negative make a positive.
so your answer is:
d^3/c^5

6 0

3 years ago

I'll give you thanks 5 starts and branliest

liq [111]

Answer:

-19

Step-by-step explanation:

apologies i did it wrong

6 0

3 years ago

Read 2 more answers