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3 years ago

Solve the Antiderivative.

Mathematics

2 answers:

vesna_86 [32]3 years ago

4 0

Ln ( | Sec (e^x + π) + tan ( e^x +π ) | )

professor190 [17]3 years ago

3 0

Answer:

I got the same as the top so I think that's the answer

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You need to convert the recipe measure of 2 quarts to both pints and fluid ounces so you enlist the help

artcher [175]

Pints: 4

Ounces: 64

Im not sure if thats what you needed but hope this helps

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3 years ago

If prices increases at a monthly rate of 2.9%, by what percentage do they increase in a year?

Amiraneli [1.4K]

I’m guessing 2.9% times 12

7 0

3 years ago

How many ways can 3 students be chosen from a class of 20 to represent their class at a banquet?

boyakko [2]

Slot method 20 options 3 slots First slot: 20 options Second slot: 19 options (one used up for 1st slot) Third slot: 18 (one less than last) Multiply them 20 times 19 times 18=6840 Answer is 6840 ways

3 0

4 years ago

Read 2 more answers

5 donuts and 2 cups of hot Chocolate costs 24$. 2 donuts and 3 cups of hot chocolate costs 14$.How much does each donut and each

Allushta [10]

Answer:cost of each donut =$4

and cost of each cup of hot chocolate =$2

Step-by-step explanation:

Step 1

Let donuts be represented as d

and cups of hot chocolate be rep as c so that

5 donuts and 2 cups of hot Chocolate costing 24$ will be expressed as

5 d+ 2 c= 24

And 2 donuts and 3 cups of hot chocolate costing 14$ will be expressed as

2d +3 c= 14

Step 2

Using elimination method,Multiply equation 1 by 3 and equation 2 by 2

15d+ 6c= 72----equation 3

4d+ 6c= 28-----equation 4

Subtracting equation 4 from equation 3 gives us

11 d=44

d= 44/11

d= 4

To find c, using equation 1

5 d+ 2 c= 24

5 x 4+ 2c=24

20+2c=24

2c=24-20

2c=4

c=4/2 =2

cost of each donut =$4

and cost of each cup of hot chocolate =$2

3 0

4 years ago

Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0

miss Akunina [59]

<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^2+y^2-2x+4y-11=0$

So, solving we have:

$x^2+y^2-2x+4y=11$

$(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16$