How many ways can 3 students be chosen from a class of 20 to represent their class at a banquet?
2 answers:
60 ways because the easy way to solve this problem is identify the numbers being used and than multiply them by each other.
Slot method
20 options
3 slots
First slot: 20 options
Second slot: 19 options (one used up for 1st slot)
Third slot: 18 (one less than last)
Multiply them
20 times 19 times 18=6840
Answer is 6840 ways
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Answer:
Step-by-step explanation:
5280*13= 68640
Answer:
X°
Step-by-step explanation:
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3/4 - 1/2 = 3/4 - 2/4 = 1/4
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147
Step-by-step explanation:
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114+33=147
180-147=33
180-33=147
The LCD here is 20. Thus, 1/4 = 5/20. The sum of 5/20 and 13/20 is 18/20, which can be reduced to 9/10 .
