What is the percent composition of C4H10?

WILL MARK BRAINLIEST!!!

Gnoma [55]

Choice 3

5/2, 15/6 divide by 3 = 5/2. 45/18 divide by 9 5/2

8 0

3 years ago

Read 2 more answers

Fined the measure of arc NL

adelina 88 [10]

The measure of an arc is twice the measure of the inscribed angle that intercepts it.

m(arc)NL = 2 * 42 = 84

5 0

3 years ago

If :

aalyn [17]

So there are 38 +32 = 70 and for the rest 30 we can assuming 15 + 8 +7

38+32+15+8+7=100

hope this will help you

3 0

3 years ago

Find the counterclockwise circulation and outward flux of the field Fequals7 xy Bold i plus 2 y squared Bold j around and over t

77julia77 [94]

Answer:

The counterclockwise circulation is $\frac{7}{12}$ and the outward flux is $\frac{11}{15}$

Step-by-step explanation:

We are given the field $F(x,y) = (7xy,2y^2)$ . A picture of the region and the path we are considering is attached. Recalll the following theorems.

Given a field of the form F(x,y)=(f(x,y),g(x,y) with f,g having continous partial derivates, C is a closed path counterclockwise oriented, R is the region enclosed by C and n is the normal vector pointing outwards of the path C. Then

$\oint_C F\cdot dr =\iint_R \frac{\partial f}{dy}- \frac{\partial g}{dx} dA$ (this one calculates the counterclockwise circulation)

$\oint_C F\cdot n ds =\iint_R (\frac{\partial f}{dx}+ \frac{\partial g}{dy} dA$ (This one calculates the outward flux)

Then, recall that in our case f(x,y) = 7xy, g(x,y)=2y^2[/tex]. Then

$\frac{\partial f}{dx} = 7y,\frac{\partial f}{dy} = 7x$

$\frac{\partial g}{dx}=0, \frac{\partial g}{dy} = 4y$ .

Note that we just need to describe our region R. The region R lies between the parabola y=x^2 and the line y=x. Thus, one way to describe the region is as follows $0\leq x \leq 1, x^2\leq y \leq x$ . Then, using the previous results, we get that

$\oint_C F\cdot dr =\int_{0}^{1}\int_{x^2}^{x}7x-0dydx = 7\int_{0}^1x(x-x^2)dx = 7 \left.(\frac{x^3}{3}-\frac{x^4}{4})\right|_{0}^1 = 7(\frac{1}{3}-\frac{1}{4}) = \frac{7}{12}$ (circulation)

$\oint_C F\cdot n ds=\int_{0}^{1}\int_{x^2}^{x}7y+4ydydx = \frac{11}{2}\int_{0}^1\left.y^2\right_{x^2}^{x}dx = \frac{11}{2}\int_{0}^{1}x^2-x^4 dx = \frac{11}{2}\left(\frac{x^3}{3}-\frac{x^5}{5})\right|_{0}^{1}=\frac{11}{2}(\frac{1}{3}-\frac{1}{5})=\frac{11}{15}$ (flux)

5 0

3 years ago

Using the distributive property to find the product (y−4x)(y2 4y 16) results in a polynomial of the form y3 4y2 ay−4xy2−axy−64x.

torisob [31]

The product (y−4x)(y^2 + 4y + 16) results in a polynomial of the form y3 4y2 ay−4xy2−axy−64x then the value of a is 16.

<h3>What is distributive property?</h3>

The distributive property states that an expression of the form A(B + C) can be solved by a multiplication over addition operation that is

A(B + C) = AB + AC

This property is known by distributive law and applies to subtraction also.

First let w = y-4x make distribution a bit easier

(y−4x)(y^2 + 4y + 16)

$w(y^2 + 4y + 16)\\wy^2 + w4y + w16\\$

now put the values of w in the equation

$(y-4x)y^2 + (y-4x)4y + (y-4x)16\\y^3-4xy^2 + 4y^2-16xy+16y-64x\\$

Here the value of a is 16.

Learn more about the distributive property:

brainly.com/question/26207297

3 0

3 years ago