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Elena-2011 [213]
2 years ago
11

You have $2500 in your bank account. It quadruples every 5 years. How

Mathematics
1 answer:
andrew-mc [135]2 years ago
5 0

Answer:

<h2>2560000</h2>

Step-by-step explanation:

2500 x 4= 10000

10,000 x 4=40,000

40,000 x 4=160,000

160,000 x 4=640,000

640,000 x 4= 2560000

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The Russian ice breaker yamal can move forward through 2.3-meter-thick ice at a speed of 5.5 kilometers per hour. Write and solv
aleksandrvk [35]

82.5 / 5.5 = 15

15 hrs.

i think that should be the answer but i didn't use the 2.3 -meter-thick clue...

8 0
3 years ago
Jayden has been reading a 275275275-page book for English class. On average, he has read about 101010 pages in 151515 minutes (\
maxonik [38]
First let's define variables:
 r: reading
 s: skimming
 We write the system of equations that adapts to the problem:
 r + s = 275
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 r = 206
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8 0
3 years ago
Solve: x - 5 = 12 A) 7 B) 16 C) 17 D) 18
postnew [5]

Answer:

The answer is option c) 17

Step-by-step explanation:

x - 5 = 12

x = 12 + 5

x = 17

The answer is c) 17

3 0
2 years ago
Read 2 more answers
WILL MARK AS BRAINLIEST The graph plots four equations, A, B, C, and D: Line A joins ordered pair negative 6, 16 and 9, negative
butalik [34]
<span>Equation B and Equation C

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7 0
3 years ago
Read 2 more answers
Select the relations that are functions.
Arlecino [84]

Answer:

Depending on how the input of each function defined,

  • The first choice \left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace,
  • The third choice \left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace
  • The fourth choice \left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

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  • map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element a from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be \lbrace a,\, 6, \, C\rbrace. Similarly, the domain for the third and fourth relations should be \lbrace 1,\, 2, \, 3\rbrace and \lbrace a,\, b, \, c\rbrace

8 0
3 years ago
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