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Y_Kistochka [10]
3 years ago
6

PLEASE HELP!!! ITS ALMOST DUE!!! ILL MARK BRAINLIEST!!

Mathematics
2 answers:
RSB [31]3 years ago
6 0

Answer:

Step-by-step explanation:

C

Natasha_Volkova [10]3 years ago
4 0

Answer: 12.8

Step-by-step explanation:

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Step-by-step explanation:

total volume= big thingy + long thingy

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Find the solutions of x and y.
sladkih [1.3K]

Answer:

x = 15, y = 4

Step-by-step explanation:

By Basic proportionality theorem, we have:

x/ 5 = 18/6

x = (18*5)/6

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Again By Basic proportionality theorem, we have:

12/y = 18/6

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6 0
3 years ago
Algebra 2A Help !<br><br> Tadakimasu ~
Ludmilka [50]
Function is p(x)=(x-4)^5(x^2-16)(x^2-5x+4)(x^3-64)

first factor into (x-r1)(x-r2)... form

p(x)=(x-4)^5(x-4)(x+4)(x-4)(x-1)(x-4)(x^2+4x+16)
group the like ones
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)

multiplicity is how many times the root repeats in the function
for a root r₁, the root r₁ multiplicity 1 would be (x-r₁)^1, multility 2 would be (x-r₁)^2 

so

p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the  root 1 and has multiplity 1
(x^2+4x+16) is not on the real plane, but the roots are -2+2i√3 and -2-2i√3, each multiplicity 1 (but don't count them because they aren't real

baseically

(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the  root 1 and has multiplity 1

7 0
3 years ago
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