Find the sum which amounts to Rs 9261 at 10% per annum compound interest for 18 months ,interest payable half yearly
, where A is amount , r is rate =10% = 0.10 , n is intervals of compounding n=2 , t is time = 18 months=1.5 years
Lets plug in
divide both sides by 1.006012008
solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
More then 2 thats the only answer I can give
Ms. Alonzo received 400 markers because one tenth of 4000 is 400. Hope this helped!
Answer:
lol same
Step-by-step explanation:
