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Lisa [10]
3 years ago
9

NEED HELP!!!!

Mathematics
1 answer:
Paha777 [63]3 years ago
6 0

Answer:

oink

Step-by-step explanation:twice a number"

→

2

n

"twice a number and k"

→

2

n

+

k

"7 less than twice a number and k"  

→

(

2

h

+

k

)

−

7

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Find the 9th term geometric sequence 1,1/2,1/2^2
valentinak56 [21]

Answer:   t_9=\dfrac{1}{2^8}

<u>Step-by-step explanation:</u>

t_n=t_1\times r^{n-1}\\\\Given: t_1=1,\quad r=\dfrac{1}{2}\\\\\\t_9=1\times\bigg(\dfrac{1}{2}\bigg)^{9-1}\\\\\\.\quad =\large\boxed{\dfrac{1}{2^8}}

3 0
3 years ago
Find the quotient: 40 ÷ 7
netineya [11]

Answer:

5.71428571429

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Suppose f(x) - x = 2/ x. Fincd f(- 3)
myrzilka [38]

Answer:

To find the mode you need to check the number which is more often repeated in the set than the other.But as you can see here there is no number which is repeated more often than the other everyone is repeated once,so in this case  we say that the set of data values has no mode.

To find the the range of the set of data you need to first place the numbers in ascending order (as it is already in) and then find the greatest and the smallest number and subtract them.

Range :

10,20,30,40,50,60,70,80,90,100,110,120,130,140,150.

Greatest number = 150.

Smallest number = 10.

Subtract = 150-10 = 140.

Step-by-step explanation:

6 0
3 years ago
Y - 1/3 is greater than 1/8
velikii [3]
If this is a true or false question, than this is true.
4 0
4 years ago
The longer leg of a right triangle is 4cm longer than the shorter leg. the hypotenuse is 8cm longer than the shorter leg. find t
Alexeev081 [22]
Longer leg = x + 4

Shorter leg = x

Hypotenuse = x + 8


Using Pythagorean Theorem:

a^2 + b^2 = c^2

(x + 4)^2 + x^2 = (x + 8)^2

x^2 + 8x + 16 + x^2 = x^2 + 16x + 64

2x^2 + 8x + 16 = x^2 + 16x + 64

2x^2 +8x = x^2 + 16x + 48

2x^2 - 8x = x^2 + 48

x^2 - 8x = 48

x^2 - 8x - 48 = 0

You can complete the square from here or use the quadratic formula.

Completing the square:

x^2 - 8x = 48

x^2 - 8x + (-8/2)^2 = 48 + (-8/2)^2

x^2 - 8x + 16 = 48 + 16

(x - 4)(x - 4) = 64 or (x - 4)^2 = 64

x - 4 = +√64 OR x - 4 = -√64

x - 4 = +8 OR x - 4 = -8

x = 12 OR x = -4

However, you can't use negative 4 as a length because your length needs to be a positive.

So x will be 12.


Shorter leg: 12

Longer leg: 12 + 4

Hypotenuse: 12 + 8

8 0
3 years ago
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