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3 years ago

I tried this few times can i get some help

Mathematics

1 answer:

mihalych1998 [28]3 years ago

6 0

Answer:

Y=4 X= -6 or (-6,4)

Step-by-step explanation:

Okay so

3x+10y=22

-3x-8y=-14

basically, it's like one big equation. First, subtract 3x from -3x which cancels out and gives us 0
10y minus 8y gives us 2y.
22 minus 14 gives us 8

3x+10y=22

0+2y=8

Now that we have this, we can solve for y. in order to do this, we have to divide both sides by 2.

$\frac{2y}{2} = \frac{8}{2}$

From here we know that y=4 because the 2s cancel out leaving y and 8 divided by 2 is 4.

y= 4

Now we can fill in. You can pick any equation for this but I'm going to chose the first one.

3x+10y=22

we can fill in 4 for y

3x+10(4)=22

3x+40=22

Next we are going to subtract 40 on both sides.

3x+40=22

-40 -40

3x= -18

Next, we're going to divide -18 by 3.

$\frac{3x}{3} = \frac{ - 18}{3}$

The 3s cancel out leaving us x. -18 divided by 3 is -6.

x= -6

Hope this helped!! :)

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3 years ago

A piece of wire 25 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

fomenos

Answer:

Wire used for square is 7.55 m.

Step-by-step explanation:

Let the length of wire cut for square be 'x'.

Given:

Total length of the wire = 25 m

Length of wire for square = 'x'

Length of wire for equilateral triangle = $25-x$

Now, area of square (a) = $x^2$

Area of equilateral triangle (e) is given as:

$e=\frac{\sqrt3}{4}(25-x)^2$

Now, total area (A) is given as:

$A=a+e\\\\A=x^2+\frac{\sqrt3}{4}(25-x)^2$

Now, in order to maximize 'A', the derivative of area with respect to 'x' must be 0.

∴ $\frac{dA}{dx}=0$

$\frac{d}{dx}(x^2+\frac{\sqrt3}{4}(25-x)^2)=0\\\\2x-\frac{\sqrt3}{2}(25-x)=0\\\\2x+\frac{x\sqrt3}{2}=\frac{25\sqrt3}{2}\\\\x(2+\frac{\sqrt3}{2})=\frac{25\sqrt3}{2}\\\\x(4+\sqrt3)=25\sqrt3\\\\x=\frac{25\sqrt3}{4+\sqrt3}=7.55\ m$

Therefore, the length of the wire that is cut for square should be 7.55 m for maximum area.

3 0

3 years ago

How do you solve √125÷√5

nordsb [41]

$\bf \sqrt{125}\div \sqrt{5}\implies \cfrac{\sqrt{125}}{\sqrt{5}}\qquad \begin{cases} 125=&5\cdot 5\cdot 5\\ &5^2\cdot 5 \end{cases}\implies \cfrac{\sqrt{5^2\cdot 5}}{\sqrt{5}} \\\\\\ \cfrac{5~~\begin{matrix} \sqrt{5} \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} \sqrt{5} \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 5$

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3 years ago

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nikitadnepr [17]

Answer: B) as x → -5 from the left, y → -∞

as x → -5 from the right, y → +∞

<u>Step-by-step explanation:</u>

$g(x) =\dfrac{x^2+15x+56}{x+5}\quad =\dfrac{(x+7)(x+8)}{x+5}\\\\\\\text{Evaluate from the left. Let x = -6}\rightarrow \dfrac{(-)(-)}{(-)}=-\\\\\\\text{Evaluate from the right. Let x = -4}\rightarrow \dfrac{(-)(-)}{(+)}=+$

Refer to the graph which confirms that

from the left, y tends toward -∞

from the right, y tends toward + ∞

3 0

3 years ago

Help me on this please

DerKrebs [107]

THIS EQUATION IS USING THE PYTHAGOREAN THEOREM
10^2 + x^2 = 14^2
100 + x^2 = 196
-100 -100
x^2 = 96
*SQUARE ROOT*
x = 9.80 (ROUNDED TO THE NEAREST HUNDREDTH)

7 0

3 years ago