1 is the 3rd option down
2 is the second option down
In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
<h3>What is the proof about?</h3>
Note that:
AB = 12
AC = 6.
BC = AB - AC
= 12 - 6
=6
So, AC, BC= 6
Since C is in the middle, one can say that C is the midpoint of AB.
Note that the use of segment addition property shows: AC + CB = AB = 12
Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6
Therefore, AC = CB and thus In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
See full question below
Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive
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Answer:
18.75%
Step-by-step explanation:
Hello,
3 students are both female and senior
the total number of students is 7+10+8+5=30
so the probability to select one female senior is 3/30=1/10=0.10
probability to select one female is 16/30=16/30
probability that the student is a senior given that it's female is
=P(female and senior)/P(female)
=1/10*30/16=3/16
hope this helps
7-4x=2-9x the answer is x=1
